Hardy Weinberg question - a level biology help??Watch
Use Hardy-Weinberg equation to calculate number of plants that were heterozygous for gene B
I've tried but I can't do it can anyone help?
The one alleles that code for yellow are aaBB, aaBb & aabb
The answer is 32%
I think this is the paper it's from - part of question 7. In that it seems to be clear that to be yellow phenotype the squashes need a B allele. The green ones are bb.
(And they're all aa – any with an A allele would be white.)
So if 36% are yellow (or 0.36 out of 1) then 64% (or 0.64 out of 1) must have the bb genotype.
Where p^2 2pq=0.36, because yellow flowers are caused by either the BB (p) allele combo or Bb (2pq) combo. bb is q.
So, 1-0.36=0.64 (q^2).
Use the equation p q=1 to find p, then subtract q and p squared from 1 to find 2pq
(ps where there are spaces there should be pluses, TSR randomly removed them)