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The idea of excess

Can anyone help with this question? I'm finding it difficult to start off.
A student prepared methanamide by the reaction of methanoic acid with ammonia.

HCOOH + NH3 --> HCONH2 +H2O
1 MOLE
HCOOH =46g NH3=17g
HCONH3 = 45g H2O=18g

2.02g of methanoic acid was reacted with 1.07g of ammonia. Show that methanoic acid is the limiting reactant.
You have found the molar masses of each reactant
Find the number of moles of each
Hence determine that methanoic acid is the limiting reactant
Do you do n=cv for methanoic acid?
Original post by BobbJo
You have found the molar masses of each reactant
Find the number of moles of each
Hence determine that methanoic acid is the limiting reactant
Original post by StuckWithWork
Do you do n=cv for methanoic acid?

No, you have the mass. The relative molecular mass is 46. Find number of moles
1 mol of HCOOH has a mass of 46 g
so ? mol HCOOH has a mass of 2.02 g
Okay thank you

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