# complex numbersWatch

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#1

I dont understand how they got the second line...how did they get (1+4n)/6 * pi?
0
4 weeks ago
#2
(Original post by ihatePE)

I dont understand how they got the second line...how did they get (1+4n)/6 * pi?
What's the question?
0
#3
(Original post by RDKGames)
What's the question?
find all possible values of z^(2/3) where z = 1 + j
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4 weeks ago
#4
(Original post by ihatePE)
find all possible values of z^(2/3) where z = 1 + j
Well if then .

Due to the cyclic behaviour of the complex numbers, we have that for any .

The next step is to take cube root of both sides, so that exponent becomes (omitting the , but it's still there). Since , the expression reduces to what you're uncertain about with the sufficient condition that in order to capture all the roots.
Last edited by RDKGames; 4 weeks ago
1
#5
(Original post by RDKGames)
Well if then .

Due to the cyclic behaviour of the complex numbers, we have that for any .

The next step is to take cube root of both sides, so that exponent becomes (omitting the , but it's still there). Since , the expression reduces to what you're uncertain about with the sufficient condition that in order to capture all the roots.
thank you very much
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