Benzene + propanoyl chloride Watch

Presto
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#1
Report Thread starter 4 weeks ago
#1
Can someone pls explain why's it B?
Why not D?

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Rultan Safeed
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This is formation of ketone.
By the following steps in Friedel Craft's Reaction.
ACYCLATION OCCURS -RCO group attaches to benzene group (R=Ch3)
here, Propanoyl chloride reacts with AlCl3, where forming an electrophile Ch3Ch2CO and forming AlCl4-
So Ch3Ch2CO attacks the benzene ring.
And ketone having a C=O have 2 Ch3 group adjacent to it.
So count benzene ring as a Ch3 group, and
and in another adjacent side Ch3Ch2.
I am sorry man, this is what i at most understand.
I am giving my A2 this may. Scared as hell.
Last edited by Rultan Safeed; 4 weeks ago
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Presto
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#3
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(Original post by Rultan Safeed)
This is formation of ketone.
By the following steps in Friedel Craft's Reaction.
ACYCLATION OCCURS -RCO group attaches to benzene group (R=Ch3)
here, Propanoyl chloride reacts with AlCl3, where forming an electrophile Ch3Ch2CO and forming AlCl4-
So Ch3Ch2CO attacks the benzene ring.
And ketone having a C=O have 2 Ch3 group adjacent to it.
So count benzene ring as a Ch3 group, and
and in another adjacent side Ch3Ch2.
I am sorry man, this is what i at most understand.
I am giving my A2 this may. Scared as hell.
It actually kinda makes sense
Thanks and same! Feel like idk anything .-.
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