Friction at inclined plane help Watch

ddsizebra
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Could someone help me out with this please?
I tried solving it myself and my answer to N (normal force) was 217N but the real answer is 309N...
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mqb2766
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How did you get 217? It seems too low even just including the box.
You also must include the normal component of P.
(Original post by ddsizebra)
Could someone help me out with this please?
I tried solving it myself and my answer to N (normal force) was 217N but the real answer is 309N...
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Views: 9
Size:  58.9 KB
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ddsizebra
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(Original post by mqb2766)
How did you get 217? It seems too low even just including the box.
You also must include the normal component of P.
I did....as x and y components since it's not strictly parallel to the plane
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ghostwalker
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(Original post by ddsizebra)
I did....as x and y components since it's not strictly parallel to the plane
Post your full working then.
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ddsizebra
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(Original post by ghostwalker)
Post your full working then.
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mqb2766
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The normal force is perpendicular to the plane only.

Edit: 300 + 80;where both are resolved perpendicular to the plane.

(Original post by ddsizebra)
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Last edited by mqb2766; 4 weeks ago
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ddsizebra
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(Original post by mqb2766)
The normal force is perpendicular to the plane only.

Edit: 300 + 80;where both are resolved perpendicular to the plane.
but how about reaction? I applied them to a previous question to solve P which i had the correct answer to
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mqb2766
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I think yourey better trying to understand the mechanics, rather than trying to spot equations.
Both gravity and the pushing exert forces on the box. They need to be resolved along and perpendicular to the plane. These should be considered independently.
(Original post by ddsizebra)
but how about reaction? I applied them to a previous question to solve P which i had the correct answer to
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