The Student Room Group

Show that this integral is inversely proportional to k [Integration Again]

So the question is:
Show that k2k2(2xk)2 \displaystyle\int^{2k}_k \dfrac{2}{(2x-k)^2} is inversely proportional to k.

And so I did successfully integrate (inbetween 2k and k) to get 23k \frac{2}{3k} but i'm not sure how proportionality comes into effect here...
i think then you've proved it then because it's 2/3k where k is a constant, so i would just write therefore it's inversely proportional but i'm also not sure
anyone else know?
Original post by ninja_uchiha
i think then you've proved it then because it's 2/3k where k is a constant, so i would just write therefore it's inversely proportional but i'm also not sure
anyone else know?

I was thinking that too but yeah i'm not exactly sure
i feel like i always become rusty in my maths ability in the holidays it's so annoying
Reply 4
If you call the integral I, then I = 2/3k

Can you see from there that as 2/3 is constant
I is proportional to the inverse of k?
Original post by Pastelx
If you call the integral I, then I = 2/3k

Can you see from there that as 2/3 is constant
I is proportional to the inverse of k?

yh that's also what i think too
Original post by ninja_uchiha
i feel like i always become rusty in my maths ability in the holidays it's so annoying

for real ****'s wild
Original post by Pastelx
If you call the integral I, then I = 2/3k

Can you see from there that as 2/3 is constant
I is proportional to the inverse of k?

To be honest I was expecting some sort of plot twist but it's still good, thanks for the confirmation man

Quick Reply