# How to solve this Maths function?Watch

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#1
F(x)= 8/x-2 + 2 , x<2

What is the range of f(x)?
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3 weeks ago
#2
All values of y I'm pretty sure
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3 weeks ago
#3
Use Desmos to be sure at https://www.desmos.com/calculator
Last edited by darkchidori925; 3 weeks ago
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3 weeks ago
#4
(Original post by olh1711)
F(x)= 8/x-2 + 2 , x<2

What is the range of f(x)?
You know the limit already for this equation already is that x<2. What it's asking is what range (how big to how small) can f(x) get?

You could find the limits by subbing in extreme values I think so for example x=-infinity, x=1.9999999999
When x=-infinity, the fraction becomes 0. 1/infinity = 0. Hence it's f(x) = 2.
Otherwise then x=1.999999, the fraction becomes 8/an infinitesimally small number. This then makes an infinitesimally big number, hence y=+infinity.

So the range that y can be is as small as 2 and as big as infinity. This can be written as:

2<y<infinity.

This means y>2 and y<infinity.

(Im rusty with maths so don't take my word on it, this is how I remember this type of thing. Wait for someone like notnek to help. )
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