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#1
Here’s the question:
A student prepares a solution of sodium sulphate by adding 6.25x10-2moldm-3 sulfuric acid from a burette to 25cm3 of 0.124moldm-3 sodium hydroxide and in a conical Flask.
Calculate the minimum volume of Sulfuric acid that the student would need to completely react with the sodium hydroxide present in cm3.

I got to 1.55x10-3 moles of sulfuric acid but then I got confused as it says you times this by (1000/6.25x10-2) in the marks scheme. I thought to calculate volume you’d do moles/conc. and then times by 1000 to get answer in cm3.
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1 month ago
#2
that's the same thing
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#3
No it isn’t. The answer is 24.8cm3 yet they way I thought you’d calculate it you get 2.48x10-3
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1 month ago
#4
(Original post by Ebonyw02xox)
No it isn’t. The answer is 24.8cm3 yet they way I thought you’d calculate it you get 2.48x10-3
(1.55 x 10^-3 / 6.25 x 10^-2) x 1000 = 1.55 x 10^-3 x (1000 / 6.25 x 10^-2)
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#5
Ok, thank you. I’ve figured it out now aha! Just being stupid 🙄
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