Iamsolostrn
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Hi, im really stuck on this question please can someone explain it, thank you so much

i) There were 500 insects in the total population. in this population 300 insects had genotype CMCM, 150 had the genotype CMCN and 50 had the genotype CNCN. Calculate the actual frequency of the allele CN by using these figures.

ii) Use your answer above and the hardy weinberg equation to calculate the number of insects that would be expected to have the genotype CNCN.

The mark scheme says the answer to i) is 0.25 and ii) is 31.25 but i cant seem to get them
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JessNaomi19600
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I tried the question but I got 0.316 as the answer:

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JessNaomi19600
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I've tried a few times and still haven't worked out how they got that answer.

Sorry I couldn't be of more help, maybe you looked at the wrong part of the mark scheme?
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Iamsolostrn
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I just double checked it is the correct part, but the question it isnt from a paper, just online questions, so maybe the mark scheme is wrong. Thank you for the help anyway though!
(Original post by JessNaomi19600)
I've tried a few times and still haven't worked out how they got that answer.

Sorry I couldn't be of more help, maybe you looked at the wrong part of the mark scheme?
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sotor
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which is the recessive allele?
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tocka90
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Try a level biology with miss jercha on youtube
HW well explained with examples!
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tocka90
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CmCm 300
CmCn 150, 150/2=75
CnCn 50

75+50=125

125/500= 0.25

Check out a level biology with miss jercha on youtube. Genetics and HW with examples and working outs!!!
(Original post by Iamsolostrn)
Hi, im really stuck on this question please can someone explain it, thank you so much

i) There were 500 insects in the total population. in this population 300 insects had genotype CMCM, 150 had the genotype CMCN and 50 had the genotype CNCN. Calculate the actual frequency of the allele CN by using these figures.

ii) Use your answer above and the hardy weinberg equation to calculate the number of insects that would be expected to have the genotype CNCN.

The mark scheme says the answer to i) is 0.25 and ii) is 31.25 but i cant seem to get them
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aquaza
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Is anyone able to do part ii? This came up in my test as the last question and I'm not sure how to get to that answer of 31.25
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Mahiraa
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q=0.25 so p=0.75 because p q=1And 2pq= 2 x 0.25 x 0.75= 0.375Rearrange the hardy Weinberg equation so q^2 = 1 - (0.75)^2 - 0.375 =1/161/16 x 500 (because population size) = 31.25
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