yeah same those two were hard. There was just so much polymerisation and most of that section was difficult for me. Did you guys get some massive number for t in the q=it question? and what did you guys put for the order of reactions?

Reply 5

gagaas

what value did u get

Original post by TheDoublethinker

That enthalpy of vapourisation question. I had never seen a question like that before. I also struggled with the proton NMR question.

Reply 6

ggspice

a massive number starting with 5

Original post by gagaas

what value did u get

and one 2nd order and one 3rd order

Reply 7

TheDoublethinker

I got first reactant 1st order, and second reactant 2nd order, and k=128 if I remember right.

The I=Q/t I got t= 1.5 •10^7 or 10^8 seconds, something like that.

(edited 4 years ago)

Reply 8

Nosy

i got order 1 and 1 and for h i got 0th order...

Reply 9

FarGang

Original post by TheDoublethinker

I got first reactant 1st order, and second reactant 2nd order, and k=128 if I remember right.

The I=Q/t I got t= 1.5 •10^7 or 10^8 seconds, something like that.

I also got first order and second order. Mine k value was 128
The question we were supposed to find the value of t, did we have to multiply the Mr of Iodine by 2? Since it was I2 (its diatomic)

Reply 10

Mohammed alomary

But the t value question if asked about lithium not iodine what t value did u get also for the half equations of chlorate ions what was the correct answer and are these right ??

Original post by FarGang

I also got first order and second order. Mine k value was 128
The question we were supposed to find the value of t, did we have to multiply the Mr of Iodine by 2? Since it was I2 (its diatomic)

Reply 11

TheDoublethinker

Original post by FarGang

I also got first order and second order. Mine k value was 128
The question we were supposed to find the value of t, did we have to multiply the Mr of Iodine by 2? Since it was I2 (its diatomic)

Do you remember the question? I think the full equation with Iodine wasn't necessary, only the half equation with Lithium on it.

So no, I think there was no need to divide. Li oxidises to Li1 , so 1 mol of Li = 1 mol of e-

(edited 4 years ago)

Reply 12

Mohammed alomary

Yah I agree but what t value did U get If u remember also were those the half equations right ?

Original post by TheDoublethinker

Reply 13

riel.iv

Original post by ggspice

a massive number starting with 5

and one 2nd order and one 3rd order

I got second order 1st order

Reply 14

Mohammed alomary

I got that too do u remember the half equations ? Were They like this ?

Original post by riel.iv

I got second order 1st order

Reply 15

Mohammed alomary

What did u write for the explanations for the ease of hydrolysis ?

Original post by riel.iv

I got second order 1st order

Reply 16

riel.iv

acyl>alkyl>aryl due to reduced charge density on carbon chlorine bond in acyl chlorides, because of the oxygen present. it's thus easily attacked. the carbon bonded to the chlorine in aryl chlorides has double bond character because the negative charge on chlorine is delocalized over the benzene ring. making it more difficult to hydrolyse

Original post by Mohammed alomary

What did u write for the explanations for the ease of hydrolysis ?

Reply 17

riel.iv

not quite...

Original post by Mohammed alomary

I got that too do u remember the half equations ? Were They like this ?

Reply 18

Mohammed alomary

Can you tell me what was your Two equations so mine are wrong ?? But don’t they lead to the same overall equation ?? Also what the t value for lithium question plzzz ??

Original post by riel.iv

not quite...

Reply 19

Mohammed alomary