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i need help with this question

The following results were recorded.
Titration number 1 2 3 4
Burette reading (final) /cm3 23.60 46.90 24.35 47.65
Burette reading (initial) /cm3 0.00 23.60 1.00 24.40
Volume of NaOH used /cm3 23.60 23.30 23.35 23.25

(iii) The uncertainty in each burette reading was ± 0.05 cm3 . Calculate the percentage uncertainty in titration number 2.

Could someone please explain how I can calculate the uncertainty?
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Mystic_
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Percentage uncertainty is calculate by the equation ((Uncertainty x number of readings) / Titre(or reading) ) x100
In this case of Titration you record 2 readings therefore the top half of the equation is (0.05 x 2)
Minus the initial reading from the final reading to find the titre (46.90 - 23.60 = 23.30)
The whole equation would be (0.1/23.30) x 100 = 0.429%. The lower the uncertainty the better.
Original post by sparklingeyz
The following results were recorded.
Titration number 1 2 3 4
Burette reading (final) /cm3 23.60 46.90 24.35 47.65
Burette reading (initial) /cm3 0.00 23.60 1.00 24.40
Volume of NaOH used /cm3 23.60 23.30 23.35 23.25

(iii) The uncertainty in each burette reading was ± 0.05 cm3 . Calculate the percentage uncertainty in titration number 2.

Could someone please explain how I can calculate the uncertainty?

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