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**CCEA A2 Level Exams 2019 - Thread for discussing thought/predictions etc **

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Original post by 134841422
find the nuclei remaining after 256 days and then subtract this from the initial nuclei number - multiply that number of nuclei with the energy per reaction then


Thanks, yeah that’s what I did, I found the paper to be a really good paper, but I guess that means the boundaries will be higher now
Original post by 134841422
Is it just me or was that the easiest fuken paper in the history of ever
I'm paranoid that I somehow accidentally missed half the paper because of how quickly and easily i finished it

Yeah I found it oddly a little too easy as well. I had extra time so had 2 and half hours.

You think its going to be scaled up?

81 raw marks were needed for A last year.
Got all these answers as well. Was weirdly easy wasn't it.
Original post by Sharpshooter
Yeah I found it oddly a little too easy as well. I had extra time so had 2 and half hours.

You think its going to be scaled up?

81 raw marks were needed for A last year.

i would imagine it would scale up a lot - hopefully i get that A
(edited 4 years ago)
also what did you guys talk about for the 6 marker question on alpha particles?

did you mention its high stability or was that irrelevant in context of the question?
Original post by Davydartboard
For the change in mass question, I did what you did, but I said the mass increased because the energy was increasing and they are proportional to eachother.

For the alpha particles 6 marker I said:
They are a helium nucleus
Consisting of 2 protons and 2 neutrons
Charge of +3.2x10^-19
Mass of 4u
Their range is a few cm in air and stopped by a sheet of paper
Their range is quite small due to their relatively large mass which makes them more likely to collide


Wrote mostly what you wrote, I mentioned a bit about their slow speed (6% of speed of light) causes them to interact more with matter thus producing more election-ion pairs, have no idea if that's what they were looking for. Was trying to fill up the paper.

It was 6 marks so were 2 marks awarded to communication and grammar?
It was 81 last year for an A, so what raw marks do you think are needed this year?
Original post by Sharpshooter
It was 81 last year for an A, so what raw marks do you think are needed this year?


my guess is like 87
Btw I also had 2.24x10^-13 for the aluminum block question.
Original post by Sharpshooter
Btw I also had 2.24x10^-13 for the aluminum block question.


right? that question was very odd

I don't get how it was a 6 marker unless i missed something
what did you guys get for the Young Modulus in first question?
How did you derive P=(1/3)p<c^2> equation?

Use density = M/v = Nm/v then sub that into PV = (1/3)Nm<c^2> equation cancelling out Nm and V?

It was only 2 marks but I can't think of any other way.
Original post by Sharpshooter
How did you derive P=(1/3)p<c^2> equation?

Use density = M/v = Nm/v then sub that into PV = (1/3)Nm<c^2> equation cancelling out Nm and V?

It was only 2 marks but I can't think of any other way.

did the same thing but the opposite way
Original post by 134841422
right? that question was very odd

I don't get how it was a 6 marker unless i missed something

Presumably it was:

1 mark for converting 12 minutes into seconds
1 mark for stating E= Pt
1 mark for working E out.
1 mark for stating E=mc^2
1 mark for rearranging for m
1 mark for your final answer.

Very generous marks though if true.
Original post by Sharpshooter
Presumably it was:

1 mark for converting 12 minutes into seconds
1 mark for stating E= Pt
1 mark for working E out.
1 mark for stating E=mc^2
1 mark for rearranging for m
1 mark for your final answer.

Very generous marking though if true.


yup - makes me afraid of how the grade boundaries are going to be like
I remember last year they dropped the A23B paper by 6% - and that paper was waay tougher than this
For the question looking for the wavelength following the excitation of electron (E = 0.084MeV).

Did you use E= hf and then sub in f for v=f lambda?

The de Broglie equation was e = h/p which you used in the final equation?
The uniform circular equation was the easiest of the lot.

I got T= 1.52N I think although I can't remember (1 point something anyway)
Original post by Sharpshooter
For the question looking for the wavelength following the excitation of electron (E = 0.084MeV).

Did you use E= hf and then sub in f for v=f lambda?

The de Broglie equation was e = h/p which you used in the final equation?


i did exactly that for first one

for Broglie equation when you say e do you mean lambda? since lambda = h/momentum
Original post by 134841422
i did exactly that for first one

for Broglie equation when you say e do you mean lambda? since lambda = h/momentum


Sorry yes I meant lambda, brains fried as I had the AS1 chemistry this morning. So 4.5 hours of exams.
did anyone talk about BE/nucleon for the 6 marker question on alpha particles?

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