**CCEA A2 Level Exams 2019 - Thread for discussing thought/predictions etc ** Watch

Davydartboard
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#41
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(Original post by 134841422)
find the nuclei remaining after 256 days and then subtract this from the initial nuclei number - multiply that number of nuclei with the energy per reaction then
Thanks, yeah that’s what I did, I found the paper to be a really good paper, but I guess that means the boundaries will be higher now
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Sharpshooter
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(Original post by 134841422)
Is it just me or was that the easiest fuken paper in the history of ever
I'm paranoid that I somehow accidentally missed half the paper because of how quickly and easily i finished it
Yeah I found it oddly a little too easy as well. I had extra time so had 2 and half hours.

You think its going to be scaled up?

81 raw marks were needed for A last year.
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Science22
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Got all these answers as well. Was weirdly easy wasn't it.
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134841422
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(Original post by Sharpshooter)
Yeah I found it oddly a little too easy as well. I had extra time so had 2 and half hours.

You think its going to be scaled up?

81 raw marks were needed for A last year.
i would imagine it would scale up a lot - hopefully i get that A
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134841422
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also what did you guys talk about for the 6 marker question on alpha particles?

did you mention its high stability or was that irrelevant in context of the question?
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Sharpshooter
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(Original post by Davydartboard)
For the change in mass question, I did what you did, but I said the mass increased because the energy was increasing and they are proportional to eachother.

For the alpha particles 6 marker I said:
They are a helium nucleus
Consisting of 2 protons and 2 neutrons
Charge of +3.2x10^-19
Mass of 4u
Their range is a few cm in air and stopped by a sheet of paper
Their range is quite small due to their relatively large mass which makes them more likely to collide
Wrote mostly what you wrote, I mentioned a bit about their slow speed (6% of speed of light) causes them to interact more with matter thus producing more election-ion pairs, have no idea if that's what they were looking for. Was trying to fill up the paper.

It was 6 marks so were 2 marks awarded to communication and grammar?
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Sharpshooter
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It was 81 last year for an A, so what raw marks do you think are needed this year?
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134841422
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(Original post by Sharpshooter)
It was 81 last year for an A, so what raw marks do you think are needed this year?
my guess is like 87
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Sharpshooter
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Btw I also had 2.24x10^-13 for the aluminum block question.
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134841422
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(Original post by Sharpshooter)
Btw I also had 2.24x10^-13 for the aluminum block question.
right? that question was very odd

I don't get how it was a 6 marker unless i missed something
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134841422
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what did you guys get for the Young Modulus in first question?
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Sharpshooter
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How did you derive P=(1/3)p<c^2> equation?

Use density = M/v = Nm/v then sub that into PV = (1/3)Nm<c^2> equation cancelling out Nm and V?

It was only 2 marks but I can't think of any other way.
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134841422
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(Original post by Sharpshooter)
How did you derive P=(1/3)p<c^2> equation?

Use density = M/v = Nm/v then sub that into PV = (1/3)Nm<c^2> equation cancelling out Nm and V?

It was only 2 marks but I can't think of any other way.
did the same thing but the opposite way
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Sharpshooter
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(Original post by 134841422)
right? that question was very odd

I don't get how it was a 6 marker unless i missed something
Presumably it was:

1 mark for converting 12 minutes into seconds
1 mark for stating E= Pt
1 mark for working E out.
1 mark for stating E=mc^2
1 mark for rearranging for m
1 mark for your final answer.

Very generous marks though if true.
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134841422
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(Original post by Sharpshooter)
Presumably it was:

1 mark for converting 12 minutes into seconds
1 mark for stating E= Pt
1 mark for working E out.
1 mark for stating E=mc^2
1 mark for rearranging for m
1 mark for your final answer.

Very generous marking though if true.
yup - makes me afraid of how the grade boundaries are going to be like
I remember last year they dropped the A23B paper by 6% - and that paper was waay tougher than this
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Sharpshooter
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For the question looking for the wavelength following the excitation of electron (E = 0.084MeV).

Did you use E= hf and then sub in f for v=f lambda?

The de Broglie equation was e = h/p which you used in the final equation?
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Sharpshooter
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The uniform circular equation was the easiest of the lot.

I got T= 1.52N I think although I can't remember (1 point something anyway)
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134841422
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(Original post by Sharpshooter)
For the question looking for the wavelength following the excitation of electron (E = 0.084MeV).

Did you use E= hf and then sub in f for v=f lambda?

The de Broglie equation was e = h/p which you used in the final equation?
i did exactly that for first one

for Broglie equation when you say e do you mean lambda? since lambda = h/momentum
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Sharpshooter
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(Original post by 134841422)
i did exactly that for first one

for Broglie equation when you say e do you mean lambda? since lambda = h/momentum
Sorry yes I meant lambda, brains fried as I had the AS1 chemistry this morning. So 4.5 hours of exams.
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134841422
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did anyone talk about BE/nucleon for the 6 marker question on alpha particles?
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