Moles AgCl = 0.610/ (108+35.5) = 4.25 x 10^-3
Ag+ + Cl- --> AgCl
so one mole of chloride ions produces one mole of precipitate,
so moles of chloride ions = 4.25 x 10^-3
Mass of Cl ions = 4.25 x 10^-3 x 35.5 = 0.15g
so 0.15g of the compound is chlorine, and 0.12g is iron
Calc the emperical formulae:
0.15/35.5 = 4.23x10^-3 mol 0.12/56 = 2.14x10^-3
Ratio Cl to iron is 2:1
So FeCl2 I think
2) Moles NaOH = 23.75/1000 x 0.1263 = 3.0 x 10^-3 moles.
RCOOH + NaOH --> RCOO-Na+ + H2O
Since R is monoprotic, 1mol NaOH reacts with 1 mole of acid to produce 1 mol of water
so moles acid = 3.0 x 10^-3 ( in 25cm^3)
Moles acid in total = 10 x 3.0x10^-3 = 0.030 (to bring up to 250cm^3)
so Mass of acid in total should = 0.030 (moles) x it's RFM
We know the mass which is 2.580g, so we must calculate the RFM
RFM = Mass/Moles = 2.580g/0.030 = 86
Acid is unsaturated so has a C=C bond...
CH(CH3)=CH-COOH