# AQA AS Further Maths Paper 1 Pure 2019 (13th May) unofficial markscheme

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How did everyone find it? It was hard to finish everything in time. Can we start an unofficial markscheme for today's paper? Thank you!!

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Specially that vector question was urggghhh

(Original post by

really hard

**√-1**)really hard

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#4

I thought it was very difficult, but could’ve been a lot worse. I find the further pure exams so pushed for time and so always end up leaving some questions blank!! hoping that the grade boundaries are as low as last year🙈

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#6

volume of revolution was 2.2 radians??

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How did everyone find it? It was hard to finish everything in time. Can we start an unofficial markscheme for today's paper? Thank you!!

**asifmahmoud**)How did everyone find it? It was hard to finish everything in time. Can we start an unofficial markscheme for today's paper? Thank you!!

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#8

**asifmahmoud**)

How did everyone find it? It was hard to finish everything in time. Can we start an unofficial markscheme for today's paper? Thank you!!

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#9

(Original post by

Pretty Hard, hopefully they'll have lowered the boundaries, though I doubt that'll happen after last year

**george_0liver29**)Pretty Hard, hopefully they'll have lowered the boundaries, though I doubt that'll happen after last year

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#12

I think the maclaurin series question was cosh(x) = 1 + x^2/2 + x^4/24 and so cosh(ix) is the same as cos(x)

for the graph of x = cosh (y+b) I got a parabola on the positive x-axis that had its minimum point at (1,0) translated down by the constant b. hence the minimum distance to the y-axis would be 1 unit

r = k / sin(theta) can be rearranged to give rsin(theta)=k which is just y=k, so a horizontal line

the proof by induction question involving the matrices could be done by multiplying A^k by A again

these are the only ones I remember off the top of my head!!

for the graph of x = cosh (y+b) I got a parabola on the positive x-axis that had its minimum point at (1,0) translated down by the constant b. hence the minimum distance to the y-axis would be 1 unit

r = k / sin(theta) can be rearranged to give rsin(theta)=k which is just y=k, so a horizontal line

the proof by induction question involving the matrices could be done by multiplying A^k by A again

these are the only ones I remember off the top of my head!!

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#13

(Original post by

What did u guys get for the last question?

**Max360**)What did u guys get for the last question?

I think p>2 because the stationary point would have to be above the x-axis for there to be no real roots

and I found the new equation by rearranging the new roots and substituting them back into the equation, giving me the value where there is no x term as ‘p+2’

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#16

this sounds promising!!! For that first one I started off accidentally using sinhx then realising it was a plus sign not a minus so I had to start again but I got that in the end!

(Original post by

I think the maclaurin series question was cosh(x) = 1 + x^2/2 + x^4/24 and so cosh(ix) is the same as cos(x)

for the graph of x = cosh (y+b) I got a parabola on the positive x-axis that had its minimum point at (1,0) translated down by the constant b. hence the minimum distance to the y-axis would be 1 unit

r = k / sin(theta) can be rearranged to give rsin(theta)=k which is just y=k, so a horizontal line

the proof by induction question involving the matrices could be done by multiplying A^k by A again

these are the only ones I remember off the top of my head!!

**lemmens**)I think the maclaurin series question was cosh(x) = 1 + x^2/2 + x^4/24 and so cosh(ix) is the same as cos(x)

for the graph of x = cosh (y+b) I got a parabola on the positive x-axis that had its minimum point at (1,0) translated down by the constant b. hence the minimum distance to the y-axis would be 1 unit

r = k / sin(theta) can be rearranged to give rsin(theta)=k which is just y=k, so a horizontal line

the proof by induction question involving the matrices could be done by multiplying A^k by A again

these are the only ones I remember off the top of my head!!

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#17

(Original post by

this is AS? did u do the A level cus the last question was about monkeys

**√-1**)this is AS? did u do the A level cus the last question was about monkeys

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#18

(Original post by

what was the final line for the hyperbolic equation?

**Max360**)what was the final line for the hyperbolic equation?

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#19

(Original post by

this sounds promising!!! For that first one I started off accidentally using sinhx then realising it was a plus sign not a minus so I had to start again but I got that in the end!

**alicestudies**)this sounds promising!!! For that first one I started off accidentally using sinhx then realising it was a plus sign not a minus so I had to start again but I got that in the end!

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#20

**lemmens**)

I think the maclaurin series question was cosh(x) = 1 + x^2/2 + x^4/24 and so cosh(ix) is the same as cos(x)

for the graph of x = cosh (y+b) I got a parabola on the positive x-axis that had its minimum point at (1,0) translated down by the constant b. hence the minimum distance to the y-axis would be 1 unit

r = k / sin(theta) can be rearranged to give rsin(theta)=k which is just y=k, so a horizontal line

the proof by induction question involving the matrices could be done by multiplying A^k by A again

these are the only ones I remember off the top of my head!!

Matrices almost ruined me as I initially tried A x A^k, but it worked once I used A^k x A

I think I got the vectors proof right, I ended up with something similar-looking to the required answer, multiplied top and bottom by 17 and got it.

For feasible values of y I got y< or equal to (7-root6)/2 and y> than or equal to (7+root6)/2

Can't remember any others

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