# Physics Edexcel Unit 1 (Old syllabus) 14 May 2019 (WPH01)Watch

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6 days ago
#21
(Original post by ree.x09)
i don’t think so.
How did you answer the projectile question?
how did you calculate the horizontal component?
there were 2 questions that were ‘show’ pretty straight forward. i think i used 1/2at^2 for the first part and got 27.6 m/s
Second part was v^2=u^2+2as and i forgot the value i got but around 2. smthn
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Thread starter 6 days ago
#22
(Original post by 686868t)
there were 2 questions that were ‘show’ pretty straight forward. i think i used 1/2at^2 for the first part and got 27.6 m/s
Second part was v^2=u^2+2as and i forgot the value i got but around 2. smthn
What did you use for the value of S? in s=1/2at^2
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6 days ago
#23
well, i hope the boundary is 45-48 for A, cz then ill prolly get the grade
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6 days ago
#24
Guys, for the projectile question, the initial velocity was 3.16 right ?? not the components.
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6 days ago
#25
the vertical height i think 19m?
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6 days ago
#26
how ?? there was no value for t ?

(Original post by 686868t)
there were 2 questions that were ‘show’ pretty straight forward. i think i used 1/2at^2 for the first part and got 27.6 m/s
Second part was v^2=u^2+2as and i forgot the value i got but around 2. smthn
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6 days ago
#27
(Original post by arhamfaisal)
how ?? there was no value for t ?
i calculated T from that then used the horizontal distance to find the velocity of the horizontal component
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6 days ago
#28
T from what ??
(Original post by 686868t)
i calculated T from that then used the horizontal distance to find the velocity of the horizontal component
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Thread starter 6 days ago
#29
(Original post by 686868t)
i calculated T from that then used the horizontal distance to find the velocity of the horizontal component
Horizontal distance=?
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Thread starter 6 days ago
#30
(Original post by arhamfaisal)
T from what ??
s=ut+1/2at^2
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6 days ago
#31
okkkkk, may god be with us. Unit 2 comin soon
(Original post by ree.x09)
s=ut+1/2at^2
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6 days ago
#32
Guys do you think the exam was difficult like the boundries will be low ??
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Thread starter 6 days ago
#33
(Original post by arhamfaisal)
okkkkk, may god be with us. Unit 2 comin soon
yeah😭
They always set higher boundaries for unit 2 than unit 1.
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Thread starter 6 days ago
#34
(Original post by Kamel1023)
Guys do you think the exam was difficult like the boundries will be low ??
it was kinda difficult. I feel like Jan 2019 was easier. Do you think the same?
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6 days ago
#35
(Original post by ree.x09)
it was kinda difficult. I feel like Jan 2019 was easier. Do you think the same?
Yes true jan 2019 was 20 times easier
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Thread starter 6 days ago
#36
(Original post by Kamel1023)
Yes true jan 2019 was 20 times easier
Yesss! the grade boundary for A was 52
So i hope this time its lower than that.
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6 days ago
#37
Yes truee
(Original post by ree.x09)
Yesss! the grade boundary for A was 52
So i hope this time its lower than that.
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6 days ago
#38
What answer did you get for workdone in maximum pull back distance
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6 days ago
#39
(Original post by ree.x09)
Horizontal distance=?
27.6 i think
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6 days ago
#40
(Original post by 686868t)
it was in metres i think
The original length was 0.70 meters.

What I don't understand is this, how come our total length must be ≤ 1 mm but our original length is 0.70 meters???

I didn't try to do any cos/sin function with the rope length (I think weight has nothing to do with those functions) so my extension came out to be something like 1.46 * 10^-4 meter or 0.13 mm or something which I added up to my original length and said it was safe since I assumed I haven't crossed the 1 mm line. Idk but were you supposed to assume that 1mm is 1 meters or something??

Overall, this was a freaking hard exam imo. I think, I didn't answer like 4-5 sub-questions since I ran out of time. Really don't know why they are making the recent questions so much harder
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