# CCEA - AS Level Unit 1 Maths, May 15thWatch

#1
Did anybody get question 7 or 9? I feel like question 9 was too confusing and ive never been asked to solve a cubic polynomial like that before.
0

5 days ago
#2
(Original post by frawding)
Did anybody get question 7 or 9? I feel like question 9 was too confusing and ive never been asked to solve a cubic polynomial like that before.
Essentially question 7 wanted you to manually apply the factor theorem, which was kinda stupid but you would've either brute forced all of the factors of 10, i.e. (x +/- 1), (x +/- 2) etc until the remainder was 0

Subbing in 2 gave you no remainder so (x-2) was a factor

Long division gave you a quadratic and you solved via the formula to get, iirc x = 2, -0.87 and 2.37

Instead of brute forcing the factors, my calculator can solve cubics so I typed the cubic in and one of the roots was x = 2, so I only proved via the factor theorem that f(2) = 0. Saved me a lot of time!

Question 9 was certainly one of the hardest questions they've ever set at AS level - and you had to know your trig very well.

Here's the way I did it - I wouldn't dwell on this paper, if you thought the rest was good, you'll be fine since the boundaries are usually lower for a new spec and because the last 2 questions caught most out
1
#3
Thanks man. I think I might have the same calculator, so i said f(2) = 0 as well, I wrote down the other two factors but I didn't really include that much working out, so I probably won't get many marks.
(Original post by mitosismeosis)
Essentially question 7 wanted you to manually apply the factor theorem, which was kinda stupid but you would've either brute forced all of the factors of 10, i.e. (x +/- 1), (x +/- 2) etc until the remainder was 0

Subbing in 2 gave you no remainder so (x-2) was a factor

Long division gave you a quadratic and you solved via the formula to get, iirc x = 2, -0.87 and 2.37

Instead of brute forcing the factors, my calculator can solve cubics so I typed the cubic in and one of the roots was x = 2, so I only proved via the factor theorem that f(2) = 0. Saved me a lot of time!

Question 9 was certainly one of the hardest questions they've ever set at AS level - and you had to know your trig very well.

Here's the way I did it - I wouldn't dwell on this paper, if you thought the rest was good, you'll be fine since the boundaries are usually lower for a new spec and because the last 2 questions caught most out
1
5 days ago
#4
(Original post by frawding)
Thanks man. I think I might have the same calculator, so i said f(2) = 0 as well, I wrote down the other two factors but I didn't really include that much working out, so I probably won't get many marks.
0
5 days ago
#5
Can anybody say what they got for question 8?
0
4 days ago
#6
(Original post by orlab123)
Can anybody say what they got for question 8?
(a^3 + 2a, 0 ), something along the lines of that, and 1 +/- root 2 for a
0
#7
I think I got that as well, it seems familiar.
(Original post by mitosismeosis)
(a^3 + 2a, 0 ), something along the lines of that, and 1 +/- root 2 for a
0
4 days ago
#8
(Original post by mitosismeosis)
(a^3 + 2a, 0 ), something along the lines of that, and 1 +/- root 2 for a
I got that as well, for 9b I got 7 which I’m pretty sure is right. I wouldn’t worry so much about 9 as it’s meant to be unreasonably difficult
0
4 days ago
#9
(Original post by OctoberRain7)
I got that as well, for 9b I got 7 which I’m pretty sure is right. I wouldn’t worry so much about 9 as it’s meant to be unreasonably difficult
Yep, I got 7 too!
0
3 days ago
#10
(Original post by orlab123)
Can anybody say what they got for question 8?
plus minus 2 root 6 I think
0
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