Edexcel AS Maths Paper 1 8MA0 Unofficial Markscheme 2019 Watch

Ryan0887
Badges: 11
Rep:
?
#81
Report 1 week ago
#81
(Original post by MrRhino)
180 - 30 - 15?
What did you get? 15 or 135?
1
reply
MrRhino
Badges: 9
Rep:
?
#82
Report 1 week ago
#82
(Original post by Ryan0887)
What did you get? 15 or 135?
I got 135 but I feel as if I may have read the question wrong.
Posted on the TSR App. Download from Apple or Google Play
Last edited by MrRhino; 1 week ago
0
reply
Ryan0887
Badges: 11
Rep:
?
#83
Report 1 week ago
#83
(Original post by MrRhino)
I got 135 but I feel as if I may have read the question wrong. 135 is correct if the 30degrees was between m and n.
the 30 was between m and n.
0
reply
Ryan0887
Badges: 11
Rep:
?
#84
Report 1 week ago
#84
(Original post by Ryan0887)
the 30 was between m and n.
The 15 was between n and m-n
0
reply
MrRhino
Badges: 9
Rep:
?
#85
Report 1 week ago
#85
(Original post by Ryan0887)
The 15 was between n and m-n
That’s what I thought.
Posted on the TSR App. Download from Apple or Google Play
Last edited by MrRhino; 1 week ago
0
reply
sealion420
Badges: 5
Rep:
?
#86
Report 1 week ago
#86
I actually went ahead and decided to draw a right angled triangle and say a^2 + b^2 = (a+b)^2 so thats why a(mag) + b(mag) = a+b(mag)
Does that sound retarded??? It said geometrically so that's all I could come up with last minute. Let me know if I'm completely out of the question rn
(Original post by helloman1)
For the last question on vectors about a+b (mag) = a (mag) + b(mag)
I just said the length of a AND b combined was equal
0
reply
sealion420
Badges: 5
Rep:
?
#87
Report 1 week ago
#87
yea SAME oof
(Original post by bellell)
I said that it didn't take into account other factors that could affect the value of the car, such as mileage and damages to the car.
0
reply
MrRhino
Badges: 9
Rep:
?
#88
Report 1 week ago
#88
(Original post by sealion420)
I actually went ahead and decided to draw a right angled triangle and say a^2 b^2 = (a b)^2 so thats why a(mag) b(mag) = a b(mag)
Does that sound retarded??? It said geometrically so that's all I could come up with last minute. Let me know if I'm completely out of the question rn
a^2 b^2 does not equal (a b)^2 for all values of a and b. For instance a right angle triangle with lengths 3, 4, 5. 3 4 doesn’t equal 5. I thought it meant that the vectors must be parallel (geometrically if you add two parallel vectors together they make a new vector of mag(a b) because you’re simply adding two lengths together as the angle is constant) [my plus signs don’t appear to be working]
Posted on the TSR App. Download from Apple or Google Play
Last edited by MrRhino; 1 week ago
0
reply
sealion420
Badges: 5
Rep:
?
#89
Report 1 week ago
#89
So how did you follow up in part 2?
(Original post by MrRhino)
a^2 b^2 does not equal (a b)^2 for all values of a and b. I thought it meant that the vectors must be parallel (geometrically if you add two parallel vectors together they make a new vector of mag(a b) because you’re simply adding two lengths together as the angle is constant)
0
reply
MrRhino
Badges: 9
Rep:
?
#90
Report 1 week ago
#90
(Original post by sealion420)
So how did you follow up in part 2?
As in with m and n?
Posted on the TSR App. Download from Apple or Google Play
0
reply
sealion420
Badges: 5
Rep:
?
#91
Report 1 week ago
#91
yes
(Original post by MrRhino)
As in with m and n?
0
reply
MrRhino
Badges: 9
Rep:
?
#92
Report 1 week ago
#92
(Original post by sealion420)
yes
Using the sin() rule: Sketch two vectors m and n with an angle of 30 between them, add a third side to create a triangle (m-n I think it was) and use sin rule to calculate the other angle which was 15 I believe. Finally 180 - 30 - 15 to get the remaining angle. (please correct me if I’m wrong)
Posted on the TSR App. Download from Apple or Google Play
Last edited by MrRhino; 1 week ago
0
reply
Ali Muhammad
Badges: 1
Rep:
?
#93
Report 1 week ago
#93
I think a B would probably be between 90-100. So you probably need another 40 marks.

(Original post by kazim323)
I think I got 53, what do you lot think i have to get on paper 2 to get a b
0
reply
ItsRyaaaaaaaan
Badges: 5
Rep:
?
#94
Report 1 week ago
#94
Do you understand how grade boundaries are set? It's +-20 marks not just 8 marks extra.
(Original post by itskxmil)
Well done idiot. Last year the A grade was 65% and I said it would be around 70% this year.
0
reply
HZ AS
Badges: 2
Rep:
?
#95
Report 1 week ago
#95
(Original post by ItsRyaaaaaaaan)
Do you understand how grade boundaries are set? It's +-20 marks not just 8 marks extra.
So what do you think will be a C?
Posted on the TSR App. Download from Apple or Google Play
1
reply
Ryan0887
Badges: 11
Rep:
?
#96
Report 1 week ago
#96
(Original post by MrRhino)
Using the sin() rule: Sketch two vectors m and n with an angle of 30 between them, add a third side to create a triangle (m-n I think it was) and use sin rule to calculate the other angle which was 15 I believe. Finally 180 - 30 - 15 to get the remaining angle. (please correct me if I’m wrong)
Yes, that's the way I did it.
0
reply
ItsRyaaaaaaaan
Badges: 5
Rep:
?
#97
Report 1 week ago
#97
Nah, our paper was very straight forward though, like if you had the knowledge then the questions didn't have much to it
(Original post by Unicornstudent)
Last years paper was so much more straight forward than this paper like yeh lots of easy ish questions but I done last years and this years and I am in Year 13 doing these I have an extra year and I found this year harder than last year
0
reply
Ryan0887
Badges: 11
Rep:
?
#98
Report 1 week ago
#98
I just said after a certain amount of years the value of the car shows no depreciation, which would be invalid.
(Original post by sealion420)
yea SAME oof
0
reply
Brain-Mind
Badges: 3
Rep:
?
#99
Report 1 week ago
#99
(Original post by ak113)
trig question:
a) Had to show that a trig identity equals to -5cosx+4
prove: (10sin^2(x) - 7cos(x) + 2) / (3 + 2cos(x)) = 4 - 5cos(x)
solve: (i didn't even have time to ****ing do it... )
(10(1 - cos^2(x)) - 7cos(x) + 2) / (3 + 2cos(x))
(10 - 10cos^2(x) - 7cos(x) + 2) / (3 + 2cos(x))
let cos(x) = x
(10 - 10x^2 - 7x + 2) / (3 + 2x)
( - 10x^2 - 7x + 12) / (3 + 2x)
- (10x^2 + 7x - 12) / (3 + 2x)
- (x - 4/5)(x + 3/2) / (3 + 2x)
- (5x - 4)(2x + 3) / (3 + 2x)
the two 2x + 3 cancel out left with:
- (5x - 4) = - 5x + 4 = 4 + 5cos(x) done.
2
reply
Brain-Mind
Badges: 3
Rep:
?
#100
Report 1 week ago
#100
(Original post by ItsEuan)
how are people finding FM so hard, it was easier than 2018 paper
i think it was mainly the time for me... and most of the people in my college...
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • Arts University Bournemouth
    Art and Design Foundation Diploma Further education
    Sat, 25 May '19
  • SOAS University of London
    Postgraduate Open Day Postgraduate
    Wed, 29 May '19
  • University of Exeter
    Undergraduate Open Day - Penryn Campus Undergraduate
    Thu, 30 May '19

How did your AQA GCSE Physics Paper 1 go?

Loved the paper - Feeling positive (351)
30.6%
The paper was reasonable (460)
40.1%
Not feeling great about that exam... (197)
17.18%
It was TERRIBLE (139)
12.12%

Watched Threads

View All