# Aqa as maths 2019 : Paper 1 // 15.05.2019

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Hi,

Could we possibly get an unofficial markscheme created for this exam?

Could we possibly get an unofficial markscheme created for this exam?

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#2

Can u please tell me what topics came up for pure maths and mechanics?

(Original post by

Hi,

Could we possibly get an unofficial markscheme created for this exam?

**Yay1601_**)Hi,

Could we possibly get an unofficial markscheme created for this exam?

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Mechanics there were some vectors on there I.e finding magnitudes.

I believe there was some use of suvat equations required and also do F = ma on linked systems so like a tractor pulling a trailer. Working out distances (s) too.

Pure.

- Co-ordinate geometry.

- Simultaneous Equations.

- Stationary points and dy/dx

- Trigonometry and identities

I can’t remember anymore.

I believe there was some use of suvat equations required and also do F = ma on linked systems so like a tractor pulling a trailer. Working out distances (s) too.

Pure.

- Co-ordinate geometry.

- Simultaneous Equations.

- Stationary points and dy/dx

- Trigonometry and identities

I can’t remember anymore.

(Original post by

Can u please tell me what topics came up for pure maths and mechanics?

**Ariana1234**)Can u please tell me what topics came up for pure maths and mechanics?

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Questions that I remember.

1. Number of solutions for tan4x

2. What does n equal

3. Find p q and then fully factorise and draw curve.

4. Trigonometry, identities, find all solutions.

5.

5. 6 marker on (2+3x)^4 - (2-3x)^4 < 32

6. Stationary points 6 marker

7. Curve equation

8. Perpendicular bisector of AB and normal to curve

9. Inverness question

10.

11. How fast

12. Which statement is true

13. Distance, max speed?

14.

15. Snapping tow bar and seconds taken to slow to 8kmh-1. (Tractor and trailer).

1. Number of solutions for tan4x

2. What does n equal

3. Find p q and then fully factorise and draw curve.

4. Trigonometry, identities, find all solutions.

5.

5. 6 marker on (2+3x)^4 - (2-3x)^4 < 32

6. Stationary points 6 marker

7. Curve equation

8. Perpendicular bisector of AB and normal to curve

9. Inverness question

10.

11. How fast

12. Which statement is true

13. Distance, max speed?

14.

15. Snapping tow bar and seconds taken to slow to 8kmh-1. (Tractor and trailer).

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#5

Thank you so much, I really appreciate it

(Original post by

Questions that I remember.

1. Number of solutions for tan4x

2. What does n equal

3. Find p q and then fully factorise and draw curve.

4. Trigonometry, identities, find all solutions.

5.

5. 6 marker on (2+3x)^4 - (2-3x)^4 < 32

6. Stationary points 6 marker

7. Curve equation

8. Perpendicular bisector of AB and normal to curve

9. Inverness question

10.

11. How fast

12. Which statement is true

13. Distance, max speed?

14.

15. Snapping tow bar and seconds taken to slow to 8kmh-1. (Tractor and trailer).

**Yay1601_**)Questions that I remember.

1. Number of solutions for tan4x

2. What does n equal

3. Find p q and then fully factorise and draw curve.

4. Trigonometry, identities, find all solutions.

5.

5. 6 marker on (2+3x)^4 - (2-3x)^4 < 32

6. Stationary points 6 marker

7. Curve equation

8. Perpendicular bisector of AB and normal to curve

9. Inverness question

10.

11. How fast

12. Which statement is true

13. Distance, max speed?

14.

15. Snapping tow bar and seconds taken to slow to 8kmh-1. (Tractor and trailer).

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Cheers.

Feeling confident?

Boundaries very low last year.

Feeling confident?

Boundaries very low last year.

(Original post by

These are my answers:

1. 8 - the forth option - not sure about this one

2. n = 6

3. p = 2, q = -3. Factorization: (x-3)(x+1)(2x+1)

4. 2√3 + 3√2 it was to express in form m√n + n√m the equation was √6/√3 - √2

5.(a) rearrange sin^2(x)+cos^2(x)=1 to find cos(x) = 1/2 and cos(x) = 1/3

(b) The angles I got the range was 0<x<720: 60, 300, 71, 431, 650, 660, 420

6. I expanded and got 162y^4 + 432 y^2 >= 0 and said that y^4 and y^2 has to be positive numbers as they have even powers

7. Stationary point at (0,-8)

8. Equation of the line for the question where it crosses at (2,0): y = -12x^-2+3

9. Showed that the perpendicular bisector has gradient of -1/3 and the tangent to the curve has gradient 3 when x = 2 and therefore the normal -1/3

10. A = 12 B = 5 N = 17 then t = 64 and later I wasn't sure and just said that 2020 would be a leap year and for the last one of that question I said that she had considered the whole year again not sure

11. 2ms^-1 or the first option

12. m is directly proportional to T the bottom option

13. (a) d = 100

(b) v = 28.4 ms^-1

(c) x<0 x>40/3

14. (a) I got vector -10i + 24j

(b) The force was equal to 13 by finding magnitude of the vector

(c) t = 1.3s

15. m = 2580 kg

T = 8856 N

t = 43s

**KA4E6**)These are my answers:

1. 8 - the forth option - not sure about this one

2. n = 6

3. p = 2, q = -3. Factorization: (x-3)(x+1)(2x+1)

4. 2√3 + 3√2 it was to express in form m√n + n√m the equation was √6/√3 - √2

5.(a) rearrange sin^2(x)+cos^2(x)=1 to find cos(x) = 1/2 and cos(x) = 1/3

(b) The angles I got the range was 0<x<720: 60, 300, 71, 431, 650, 660, 420

6. I expanded and got 162y^4 + 432 y^2 >= 0 and said that y^4 and y^2 has to be positive numbers as they have even powers

7. Stationary point at (0,-8)

8. Equation of the line for the question where it crosses at (2,0): y = -12x^-2+3

9. Showed that the perpendicular bisector has gradient of -1/3 and the tangent to the curve has gradient 3 when x = 2 and therefore the normal -1/3

10. A = 12 B = 5 N = 17 then t = 64 and later I wasn't sure and just said that 2020 would be a leap year and for the last one of that question I said that she had considered the whole year again not sure

11. 2ms^-1 or the first option

12. m is directly proportional to T the bottom option

13. (a) d = 100

(b) v = 28.4 ms^-1

(c) x<0 x>40/3

14. (a) I got vector -10i + 24j

(b) The force was equal to 13 by finding magnitude of the vector

(c) t = 1.3s

15. m = 2580 kg

T = 8856 N

t = 43s

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#7

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#8

I’m doing the AS exam as my mock as I do A level so if anyone can provide any more information about the questions I’d appreciate it. Tryna get a high predicted grade ahaha thanks

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#9

Did you actually get all these answers Bad for me as I didn't have enough time! You seem very confident so well done but I'm dreading stats

(Original post by

These are my answers:

1. 8 - the forth option - not sure about this one

2. n = 6

3. p = 2, q = -3. Factorization: (x-3)(x+1)(2x+1)

4. 2√3 + 3√2 it was to express in form m√n + n√m the equation was √6/√3 - √2

5.(a) rearrange sin^2(x)+cos^2(x)=1 to find cos(x) = 1/2 and cos(x) = 1/3

(b) The angles I got the range was 0<x<720: 60, 300, 71, 431, 650, 660, 420

6. I expanded and got 162y^4 + 432 y^2 >= 0 and said that y^4 and y^2 has to be positive numbers as they have even powers

7. Stationary point at (0,-8)

8. Equation of the line for the question where it crosses at (2,0): y = -12x^-2+3

9. Showed that the perpendicular bisector has gradient of -1/3 and the tangent to the curve has gradient 3 when x = 2 and therefore the normal -1/3

10. A = 12 B = 5 N = 17 then t = 64 and later I wasn't sure and just said that 2020 would be a leap year and for the last one of that question I said that she had considered the whole year again not sure

11. 2ms^-1 or the first option

12. m is directly proportional to T the bottom option

13. (a) d = 100

(b) v = 28.4 ms^-1

(c) x<0 x>40/3

14. (a) I got vector -10i + 24j

(b) The force was equal to 13 by finding magnitude of the vector

(c) t = 1.3s

15. m = 2580 kg

T = 8856 N

t = 43s

**KA4E6**)

These are my answers:

1. 8 - the forth option - not sure about this one

2. n = 6

3. p = 2, q = -3. Factorization: (x-3)(x+1)(2x+1)

4. 2√3 + 3√2 it was to express in form m√n + n√m the equation was √6/√3 - √2

5.(a) rearrange sin^2(x)+cos^2(x)=1 to find cos(x) = 1/2 and cos(x) = 1/3

(b) The angles I got the range was 0<x<720: 60, 300, 71, 431, 650, 660, 420

6. I expanded and got 162y^4 + 432 y^2 >= 0 and said that y^4 and y^2 has to be positive numbers as they have even powers

7. Stationary point at (0,-8)

8. Equation of the line for the question where it crosses at (2,0): y = -12x^-2+3

9. Showed that the perpendicular bisector has gradient of -1/3 and the tangent to the curve has gradient 3 when x = 2 and therefore the normal -1/3

10. A = 12 B = 5 N = 17 then t = 64 and later I wasn't sure and just said that 2020 would be a leap year and for the last one of that question I said that she had considered the whole year again not sure

11. 2ms^-1 or the first option

12. m is directly proportional to T the bottom option

13. (a) d = 100

(b) v = 28.4 ms^-1

(c) x<0 x>40/3

14. (a) I got vector -10i + 24j

(b) The force was equal to 13 by finding magnitude of the vector

(c) t = 1.3s

15. m = 2580 kg

T = 8856 N

t = 43s

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#10

(Original post by

Did you actually get all these answers Bad for me as I didn't have enough time! You seem very confident so well done but I'm dreading stats

**gnuehc128**)Did you actually get all these answers Bad for me as I didn't have enough time! You seem very confident so well done but I'm dreading stats

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#11

(Original post by

First thank you and yes I got these I'm not saying that they are 100% correct but I found the test easy.

**KA4E6**)First thank you and yes I got these I'm not saying that they are 100% correct but I found the test easy.

1. 4 not 8.

5(b) - actually 6(b) - you seem to have given the angles for 2x (0<=2x<=720) rather than x (0<=x<=360)

10(a)(ii) B=6 not 5, (a)(iv) t=51 (you would probably get ECF marks) and (a)(v) is because sin works on 360 degrees/days but there are 365 days in a year

13(c) Explicitly discard x<0 as time cannot be negative

14(a) wanted

**distance**not displacement, so 26m. 14(c)(ii) is 1.8s

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#12

(Original post by

They are mostly spot on. Only mistakes are:

13(c) Explicitly discard x<0 as time cannot be negative

**pirsquared80**)They are mostly spot on. Only mistakes are:

13(c) Explicitly discard x<0 as time cannot be negative

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What does everyone think the grade boundary for an A would be? My guess is higher but how much?

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My answers were similar except

Q10. B = 6 and t = 65.

I messed up Q15 because I rushed and got stupid answers such as 12,000kg for the mass and 200 odd seconds 😂.

Also didn’t finish question 6 as I had little time.

Other than that some minor mistakes could have cost me too.

Q10. B = 6 and t = 65.

I messed up Q15 because I rushed and got stupid answers such as 12,000kg for the mass and 200 odd seconds 😂.

Also didn’t finish question 6 as I had little time.

Other than that some minor mistakes could have cost me too.

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#15

I reckon that it will be no less than 50/80. The questions were easy, but there were many traps such as rounding too early in the trig question.

(Original post by

What does everyone think the grade boundary for an A would be? My guess is higher but how much?

**Yay1601_**)What does everyone think the grade boundary for an A would be? My guess is higher but how much?

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#16

(Original post by

They are mostly spot on. Only mistakes are:

1. 4 not 8.

5(b) - actually 6(b) - you seem to have given the angles for 2x (0<=2x<=720) rather than x (0<=x<=360)

10(a)(ii) B=6 not 5, (a)(iv) t=51 (you would probably get ECF marks) and (a)(v) is because sin works on 360 degrees/days but there are 365 days in a year

13(c) Explicitly discard x<0 as time cannot be negative

14(a) wanted

**pirsquared80**)They are mostly spot on. Only mistakes are:

1. 4 not 8.

5(b) - actually 6(b) - you seem to have given the angles for 2x (0<=2x<=720) rather than x (0<=x<=360)

10(a)(ii) B=6 not 5, (a)(iv) t=51 (you would probably get ECF marks) and (a)(v) is because sin works on 360 degrees/days but there are 365 days in a year

13(c) Explicitly discard x<0 as time cannot be negative

14(a) wanted

**distance**not displacement, so 26m. 14(c)(ii) is 1.8s
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#17

(Original post by

I’m doing the AS exam as my mock as I do A level so if anyone can provide any more information about the questions I’d appreciate it. Tryna get a high predicted grade ahaha thanks

**connort2001**)I’m doing the AS exam as my mock as I do A level so if anyone can provide any more information about the questions I’d appreciate it. Tryna get a high predicted grade ahaha thanks

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#18

(Original post by

I reckon that it will be no less than 50/80. The questions were easy, but there were many traps such as rounding too early in the trig question.

**The Big Cheese**)I reckon that it will be no less than 50/80. The questions were easy, but there were many traps such as rounding too early in the trig question.

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I reckon it’ll be around the 100 Mark this time round.

(Original post by

Last year it was 80 total on both papers for an A which isn’t bad tbh

**annoymous_**)Last year it was 80 total on both papers for an A which isn’t bad tbh

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#20

(Original post by

I reckon it’ll be around the 100 Mark this time round.

**Yay1601_**)I reckon it’ll be around the 100 Mark this time round.

Starting from the instant the tow bar breaks calculate the time taken until the speed of trailer gets somethign reduced to 9

what did u get for dis one

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