# Edexcel IAL Physics unit 2 (Old Syllabus) WPH02 May 2019Watch

Announcements
#1
Hello everyone, this thread is For physics old syllabus. The exam is on 17 may. Feel free to discuss your problems and ask questions here.

January 2019 Papers can be found here: https://m.facebook.com/notes/edumaes...36083640431373

For unit 2 notes, you can use physicsmathstutor.com
2
5 days ago
#2
Hellooo!
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#3
(Original post by ree.x09)
Hellooo!
Hi
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5 days ago
#4
Do you have any revision note containing a list of all the definitions required for unit 2?
1
5 days ago
#5
Will solving papers from 2019jan to 2015 be enough?
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#6
(Original post by ree.x09)
Will solving papers from 2019jan to 2015 be enough?
Yeah I think its enough. Go to physics maths tutor and they have flashcards for definitions. Most of the definitions are from electricity
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5 days ago
#7
(Original post by usman200186)
Yeah I think its enough. Go to physics maths tutor and they have flashcards for definitions. Most of the definitions are from electricity
Thanks a lot. You’re really helpful!
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#8
How do we find radiation flux? I cannot ffind any formula in my book.....
And what about the 2nd part? We divide 4590J by 110J
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#9
And I have another question, why is it beneficial to use potential divider in a circuit?
0
5 days ago
#10
(Original post by usman200186)
How do we find radiation flux? I cannot ffind any formula in my book.....
And what about the 2nd part? We divide 4590J by 110J
The first part is easy. You're told to find Radiation Flux (A.K.A Intensity) and Intensity = Power / Area (Check the back of your book if you're using the Miles Hudson one)
Since you're given energy, you can use, Power = Energy / Time and find intensity afterwards (P.S. Time is 1 hours so 602 seconds)

2nd part states that, you need to find the efficiency which is, (Useful Energy Output / Total Energy Input) x 100 ---> Here that'd be, (110 J / 4590 J) * 100 = 2.4%

(Original post by usman200186)
And I have another question, why is it beneficial to use potential divider in a circuit?
I've also found these 2 links:

(1) https://en.wikipedia.org/wiki/Voltage_divider
(2) https://www.quora.com/What-are-the-a...oltage-divider

Let me know where you found the potential divider question so I could see the mark scheme and compare my answers. Cheers!
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#11
(Original post by mechguffin)
I've also found these 2 links:

(1) https://en.wikipedia.org/wiki/Voltage_divider
(2) https://www.quora.com/What-are-the-a...oltage-divider

Let me know where you found the potential divider question so I could see the mark scheme and compare my answers. Cheers!
Thank you soo much for explaining all this cu i was a bit confused in intensity and radiation flux, but they are just the same thing. this past paper is january (IAL) 2017
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5 days ago
#12
Yeah i don’t understand the potential divider questions at all. What does a potential divider do? Can someone please explain in short? Or links to any videos?
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#13
(Original post by ree.x09)
Yeah i don’t understand the potential divider questions at all. What does a potential divider do? Can someone please explain in short? Or links to any videos?
Same, my concept is that potential divider changes the voltage in circuit like it can control the circuit. Cuz if you change voltage, the current changes so does resistance.
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4 days ago
#14
Can someone please explain me how 13(c) is done. Which formula they using?
Attachment 818896
Attachment 818898
Here’s the markscheme
Attachment 818900
Last edited by ree.x09; 4 days ago
0
4 days ago
#15
(Original post by usman200186)
And I have another question, why is it beneficial to use potential divider in a circuit?
You can reduce the p.d to 0
It does not affect the current
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4 days ago
#16
(Original post by ree.x09)
Can someone please explain me how 13(c) is done. Which formula they using?
Attachment 818896
Attachment 818898
Here’s the markscheme
Attachment 818900
13 c) u use the equation hf=work function +K.E
the mass in KE will be the mass of an electron (found in ur data booklet) andddd thats it?
0
4 days ago
#17
(Original post by usman200186)
Same, my concept is that potential divider changes the voltage in circuit like it can control the circuit. Cuz if you change voltage, the current changes so does resistance.
same here, spent all of yesterday finding anything to explain it but basically it doesnt affect the current
so rheostats (variable resistors) alter the current
Potential dividers alters the voltage
just remember that i guess😂
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4 days ago
#18
Guys pleasee can anyone explain to me the answer to this question (second part)
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4 days ago
#19
(Original post by 686868t)
Guys pleasee can anyone explain to me the answer to this question (second part)
You gotta use ratios.

R1 / R2 = R3 / R4

120 / 295 = 110 / R4 ----> R4 = 110 / (120/295) ---> R = 270 Ohms
1
4 days ago
#20
(Original post by mechguffin)
You gotta use ratios.

R1 / R2 = R3 / R4

120 / 295 = 110 / R4 ----> R4 = 110 / (120/295) ---> R = 270 Ohms
thankss!
0
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