Physics AS level multiple choice question Watch

ZedEmDoubleU
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Can someone please help me with this question?
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this is 9701/11/o/n/15 q5
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esrever
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(Original post by ZedEmDoubleU)
Can someone please help me with this question?
Name:  halp.PNG
Views: 7
Size:  27.3 KB
this is 9701/11/o/n/15 q5
is it B?
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ZedEmDoubleU
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yes indeed!
can you please explain why it can't be C ?

(Original post by esrever)
is it B?
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esrever
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I did this last year so my solution may be wrong.

For each reading, total absolute uncertainty is 0.1 + 0.1 = 0.2. Now since there are four readings, you have to divide this uncertainty by 4 to get uncertainty of average as 0.2/4 = 0.05.
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ZedEmDoubleU
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tru, but the calculated value, shouldn't it be to the same number of sig figs as the raw data?
so the value of the width
should be to 2 s.f.
(Original post by esrever)
I did this last year so my solution may be wrong.

For each reading, total absolute uncertainty is 0.1 + 0.1 = 0.2. Now since there are four readings, you have to divide this uncertainty by 4 to get uncertainty of average as 0.2/4 = 0.05.
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esrever
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(Original post by ZedEmDoubleU)
tru, but the calculated value, shouldn't it be to the same number of sig figs as the raw data?
Averaging increases the accuracy. In general, no. of sig figs of a calculated value should only depend on absolute uncertainty.
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ZedEmDoubleU
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Oh didnt know that, thanks !

(Original post by esrever)
Averaging increases the accuracy. In general, no. of sig figs of a calculated value should only depend on absolute uncertainty.
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