# Physics AS level multiple choice questionWatch

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Thread starter 5 days ago
#1
Can someone please help me with this question?

this is 9701/11/o/n/15 q5
Last edited by ZedEmDoubleU; 5 days ago
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5 days ago
#2
(Original post by ZedEmDoubleU)
Can someone please help me with this question?

this is 9701/11/o/n/15 q5
is it B?
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Thread starter 5 days ago
#3
yes indeed!
can you please explain why it can't be C ?

(Original post by esrever)
is it B?
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5 days ago
#4
I did this last year so my solution may be wrong.

For each reading, total absolute uncertainty is 0.1 + 0.1 = 0.2. Now since there are four readings, you have to divide this uncertainty by 4 to get uncertainty of average as 0.2/4 = 0.05.
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Thread starter 5 days ago
#5
tru, but the calculated value, shouldn't it be to the same number of sig figs as the raw data?
so the value of the width
should be to 2 s.f.
(Original post by esrever)
I did this last year so my solution may be wrong.

For each reading, total absolute uncertainty is 0.1 + 0.1 = 0.2. Now since there are four readings, you have to divide this uncertainty by 4 to get uncertainty of average as 0.2/4 = 0.05.
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5 days ago
#6
(Original post by ZedEmDoubleU)
tru, but the calculated value, shouldn't it be to the same number of sig figs as the raw data?
Averaging increases the accuracy. In general, no. of sig figs of a calculated value should only depend on absolute uncertainty.
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Thread starter 5 days ago
#7
Oh didnt know that, thanks !

(Original post by esrever)
Averaging increases the accuracy. In general, no. of sig figs of a calculated value should only depend on absolute uncertainty.
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