Edexcel Further Maths AS Paper 2 16th May 2019 Watch

hassanm12345
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I did mechanics and decision. Horrible paper
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NATHan w
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I found the mechanics fine and decision hard
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hassanm12345
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What did you get for the restitution part
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Poppy Gerrard
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I did edexcel decision AS paper and thought it was hard too. The dijkstras question and the last linear programme one was awful
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dvnowombat
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I couldn't do the last mechanics question. Assumed that the velocity of Q is negative then tried using law of restitution & conservation of momentum, but then couldn't cancel out the velocities in the inequality.
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FirstAstroRook
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I did Further Pure 1 and Decision 1; Decision section was similar to 2018... both were alright
(Original post by Poppy Gerrard)
I did edexcel decision AS paper and thought it was hard too. The dijkstras question and the last linear programme one was awful
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IntenseFluff
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What did you get for the coordinates of P in further pure? the last 10 marker
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FirstAstroRook
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x coordinate: 4/(root(2))

y coordinate: 4*(root(2))

Not sure if I m rite
(Original post by IntenseFluff)
What did you get for the coordinates of P in further pure? the last 10 marker
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Batiboi
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I got ( 2 root 2 , 4 root 2)
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Kaushik mysore
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I got the same answer
(Original post by FirstAstroRook)
x coordinate: 4/(root(2))

y coordinate: 4*(root(2))

Not sure if I m rite
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FirstAstroRook
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#11
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You are right also. as 2 root 2 = 4/(root(2))


(Original post by Batiboi)
I got ( 2 root 2 , 4 root 2)
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rose236
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yeah i got that too
(Original post by Batiboi)
I got ( 2 root 2 , 4 root 2)
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Kaushik mysore
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What did you get for the range of values of k for which there is a second collision?
This is from FM1
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RedGiant
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I did stats and mechanics. Stats was pretty easy IMO, mechanics wasn’t too bad either.

I got k>1/e, v=10, can’t remember much else.
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Last edited by RedGiant; 1 week ago
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IntenseFluff
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(Original post by Kaushik mysore)
What did you get for the range of values of k for which there is a second collision?
This is from FM1
k > 1/e
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Tom Alder
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Yeah same. That was such a satisfying question and papers were fairly easy
(Original post by FirstAstroRook)
You are right also. as 2 root 2 = 4/(root(2))
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Kaushik mysore
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What was the value of e for the two particle collision?
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Kaushik mysore
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And the KE lost...
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IntenseFluff
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(Original post by Kaushik mysore)
What was the value of e for the two particle collision?
Struggled with that question how do you do it?
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NATHan w
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(Original post by Kaushik mysore)
What was the value of e for the two particle collision?
e was 7/18
v was 10 (power question)
v was 9.4 2 sf (parcel down a slope)
messed up last question about k, I formed my equation and got to the part where it was less zero so hopefully I don’t lose too many marks
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