Gcse combined science trilogy physics paper 1 (higher) aqa - unofficial mark scheme Watch

KINGAMAN10
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#1
This exam isn’t till the 22nd but everyone please share the answers that you think are right after doing the exam.
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Pro Gamer 2003
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The answer to physics is calculations.
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Paolo3100
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The answer to the 6 marker was 40
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max pays
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what 6 markers?
(Original post by Paolo3100)
The answer to the 6 marker was 40
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archiedunne2002
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I got 40 for the 6 mark specific heat thing
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max pays
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(Original post by archiedunne2002)
I got 40 for the 6 mark specific heat thing
how, it was asking for the specific heat capacity of water?
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Sammmyuel12
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I got 4800 for spec heat cap
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max pays
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for the specific heat capacity of water, it was 4751, converted to 2sf is 4800
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Sammmyuel12
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6 marker on specific heat capacity:
Had to calculate E(energy transferred) by using E = P X T as you were given the power and time was 120 seconds if I tenner correctly. However the power was in Kw so you needed to convert to watts. Then sub in to specific heat capacity equation.
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Iamthatkid212
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yeh, i used the energy transfered equation [power(W) x time(s)]. converted kW to W and i got 312000J. Rearranged the specific heat capacity equation to find specific heat capacity and got 48000J/kg °C

(Original post by Sammmyuel12)
I got 4800 for spec heat cap
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Iamthatkid212
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how did you get that mate? i got 4800J/kg°C

(Original post by Paolo3100)
The answer to the 6 marker was 40
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Paolo3100
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(Original post by Iamthatkid212)
how did you get that mate? i got 4800J/kg°C
2.6 x 1000 = 2600
2600÷(0.80x80) = 40
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Pro Gamer 2003
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Yeah I got it 6 marks in the bag.
(Original post by Sammmyuel12)
I got 4800 for spec heat cap
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Iamthatkid212
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No mate, first part is correct but then you would multiply 2600W by 120s to give 312000J and then do 312000/(0.80 x 82) = 4756.09756
= 4800J/kg°C
(Original post by Paolo3100)
2.6 x 1000 = 2600
2600÷(0.80x80) = 40
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Umsr
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how was the specific heat capacity question worded? can't seem to remember it
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Paolo3100
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did the paper have two 6 markers?
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poppywillow
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Yeah, one was about the movement of air molecules of the different states of argon, and the other was a calculation of specific heat capacity
(Original post by Paolo3100)
did the paper have two 6 markers?
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2k19GCSES
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anyone else get something like 0.1212 for the mass of water
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Mzhax
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(Original post by Paolo3100)
The answer to the 6 marker was 40
no it wasnt ur meant to use another equation because u needed thermal energy change
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georgiamaegriff
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#20
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Did anyone get 14:19 for ratio question at the end?
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