AS Physics questions (CIE)Watch

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#1
Good morning, I would like some help in the following questions please:

1.
https://www.cienotes.com/wp-content/..._s15_qp_22.pdf

In question 5a) how would the graph look like?
Since with increasing temperature resistance decreases, would the graph be a decreasing gradient from 0 to 100?
Part 5b iv) No idea, I know with increasing temp, voltage increases.
But don't know why p.d across Z would decrease.

2.
https://www.cienotes.com/wp-content/...17_qp_22-1.pdf

I did answer these questions but I just wanted to confirm if I got the idea right. In question cii)1. If the phase difference was 90 or 270, then the waves would be out of phase, and if phase difference was 0, 180 and 36, in phase?

3.
https://www.cienotes.com/wp-content/...17_qp_23-1.pdf

Question 6bi)2. The bulbs are connected in parallel, so if the voltage across each loop is 12V shouldnt the current in circuit be 4.0V from the graph? MS answer is 8V.

4.
https://www.cienotes.com/wp-content/..._w15_qp_22.pdf

In question 7c)i) If the path difference would be 2λ instead of λ
Would the amplitude be 4 x 3.2mm ? Since for λ the amplitude is 2 x 3.2mm.

5.
https://www.cienotes.com/wp-content/..._s16_qp_21.pdf

No idea how to do question 6c)iii).

Would appreciate help asap since I have the exam tomorrow Last edited by Jian17; 1 month ago
0
1 month ago
#2
First paper 5a yes, its a decaying curve - google "resistance temperature thermistor" and you'll see a bundle of examples.
5b (iv) if the temp increases, then the resistance of Z will decrease and the voltage across it will decrease. (Plug in a smaller value for the resistance of Z and work out the new voltage if you're not sure.)

Second paper - if the phase difference was changed by 90deg then what was constructive before will now be destructive and vice versa.

Third paper 6b(i) 2 The voltage across each bulb is 12v and the current through each bulb is 4A. These two currents add together where the two branches rejoin to give a total of 8A.

Fourth paper - not sure I'm looking at the same one as you!!

Fifth paper, The ratio of resistances of Y and Z are RY/RZ = 2/1 So let Z have a resistance R ohms then Y will have a resistance 2R ohms. The total resistance in the circuit will be 3R ohms and therefore the current will be 12/(3R). So, the voltage across Y VY = current * 2R = (12/(3R))*2R = 8V.
1
#3
Thank you very much! Now to wait if someone can respond to my doubt in the fourth paper (Original post by Teenie2)
First paper 5a yes, its a decaying curve - google "resistance temperature thermistor" and you'll see a bundle of examples.
5b (iv) if the temp increases, then the resistance of Z will decrease and the voltage across it will decrease. (Plug in a smaller value for the resistance of Z and work out the new voltage if you're not sure.)

Second paper - if the phase difference was changed by 90deg then what was constructive before will now be destructive and vice versa.

Third paper 6b(i) 2 The voltage across each bulb is 12v and the current through each bulb is 4A. These two currents add together where the two branches rejoin to give a total of 8A.

Fourth paper - not sure I'm looking at the same one as you!!

Fifth paper, The ratio of resistances of Y and Z are RY/RZ = 2/1 So let Z have a resistance R ohms then Y will have a resistance 2R ohms. The total resistance in the circuit will be 3R ohms and therefore the current will be 12/(3R). So, the voltage across Y VY = current * 2R = (12/(3R))*2R = 8V.
0
1 month ago
#4
Found the marking scheme!
(c) (i) path difference is λ
water vibrates/oscillates with amplitude about 2 × 3.2mm
(ii) path difference is λ / 2 so little/no motion/displacement/amplitude
0
#5
My doubt is whether having a path difference of 2λ means amplitude would be x4?
My guess is no.
(Original post by Teenie2)
Found the marking scheme!
(c) (i) path difference is λ
water vibrates/oscillates with amplitude about 2 × 3.2mm
(ii) path difference is λ / 2 so little/no motion/displacement/amplitude
0
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