# Integration Maths QuestionWatch

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#1
Using integration by substitution find the indefinite integral of :
x(3x-2)^1/2 dx. u=3x-2

0
3 weeks ago
#2
If u = 3x - 2 then x = (u + 2) / 3, hence you can substitute that x at the front with (u + 2) / 3
Then substitute u = 3x-2 inside the square root, and then multiply everything inside the integral by dx/du, and then you can integrate
0
3 weeks ago
#3
u = 3x - 2, and therefore x = (1/3) * (u+2).
du/dx = 3, so dx = (1/3) du
Substitute these into x(3x-2)1/2 dx and then you have an expression in u and du which you can multiply out and then integrate.
0
3 weeks ago
#4
(Original post by jason0597)
If u = 3x - 2 then x = (u + 2) / 3, hence you can substitute that x at the front with (u + 2) / 3
Then substitute u = 3x-2 inside the square root, and then multiply everything inside the integral by dx/du, and then you can integrate
Snap!
0
#5
Thanks Everyone!
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