well there's 6.022 x 10^23 molecules of gas in 28g 28/6 = 4.7 so assuming you divide 6.022 x 10^23 by 4.7 to get the number of molecules of gas in 6g? So 1.3 x 10^23?
well there's 6.022 x 10^23 molecules of gas in 28g 28/6 = 4.7 so assuming you divide 6.022 x 10^23 by 4.7 to get the number of molecules of gas in 6g? So 1.3 x 10^23?
yep! be careful of rounding errors, you should have 1.29*10^23. I did (6/28)*(6.02*10^23) but if your way makes sense to you then stick with that
first find the number of moles Mr(N2) = 14X2 = 28mass = 6.0gn(mol)= mass/Mr = 6/28 =Ans number of 1 proton = 6.022x10^23 x Ans = Ans2Nitrogen(N) has 7 protons where as N2 would have x2 = 14total protons in N2 gas 14 x Ans 2
1.) Work out moles of Nitrogen : 6g/14 = 0.42892.) Workout the number of particles by multiplying the moles by Avogadro's constant : 0.04289 x 6.022x10^23 = 2.58 x10^23.3.) Because there are 7 protons in each particle of N, multiply your anwser by 7 which give syou 1.8 x10^24.
1.) Work out moles of Nitrogen : 6g/14 = 0.42892.) Workout the number of particles by multiplying the moles by Avogadro's constant : 0.04289 x 6.022x10^23 = 2.58 x10^23.3.) Because there are 7 protons in each particle of N, multiply your anwser by 7 which give syou 1.8 x10^24.
Wouldn’t you multiply by 14 because it’s N2 so (7+7) = 14 protons
Wouldn’t you multiply by 14 because it’s N2 so (7+7) = 14 protons
they worked out the moles of one atom of nitrogen so they did the protons per atom. I suggest doing it the other guy's way where you take into account it's diatomic and that you multiply it by 14 in the end