Avogadro constant help please

How many protons are there in 6.0g of nitrogen gas?
Avogadro constant = 6.022 x 10^23 mol-1

Answer is 1.8 x 10^24
How do I get to this?

How many protons are there per molecule of N2?

14?

how many molecules of gas in 6g?

well there's 6.022 x 10^23 molecules of gas in 28g
28/6 = 4.7
so assuming you divide 6.022 x 10^23 by 4.7 to get the number of molecules of gas in 6g? So 1.3 x 10^23?

yep! be careful of rounding errors, you should have 1.29*10^23.
I did (6/28)*(6.02*10^23) but if your way makes sense to you then stick with that

so how many protons in 1.3*10^23?

only thing I can think of is 1.29 x 10^23 x 14? But I don't really understand why that is

yep! if you have 14 protons in every molecule, then in 100 molecules you have 100x14 protons

and if you have 1.29*10^23 molecules, you get your answer

does that make sense?

1.) Work out moles of Nitrogen : 6g/14 = 0.42892.) Workout the number of particles by multiplying the moles by Avogadro's constant : 0.04289 x 6.022x10^23 = 2.58 x10^23.3.) Because there are 7 protons in each particle of N, multiply your anwser by 7 which give syou 1.8 x10^24.

Wouldn’t you multiply by 14 because it’s N2 so (7+7) = 14 protons

yep! if you have 14 protons in every molecule, then in 100 molecules you have 100x14 protons

and if you have 1.29*10^23 molecules, you get your answer

does that make sense?