# Avogadro constant help please

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Thread starter 2 years ago
#1
How many protons are there in 6.0g of nitrogen gas?
Avogadro constant = 6.022 x 10^23 mol-1

Answer is 1.8 x 10^24
How do I get to this?
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2 years ago
#2
(Original post by anactualmess)
How many protons are there in 6.0g of nitrogen gas?
Avogadro constant = 6.022 x 10^23 mol-1

Answer is 1.8 x 10^24
How do I get to this?
How many protons are there per molecule of N2?
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Thread starter 2 years ago
#3
14?
(Original post by Pigster)
How many protons are there per molecule of N2?
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2 years ago
#4
(Original post by anactualmess)
14?
how many molecules of gas in 6g?
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Thread starter 2 years ago
#5
well there's 6.022 x 10^23 molecules of gas in 28g
28/6 = 4.7
so assuming you divide 6.022 x 10^23 by 4.7 to get the number of molecules of gas in 6g? So 1.3 x 10^23?
(Original post by sotor)
how many molecules of gas in 6g?
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2 years ago
#6
(Original post by anactualmess)
well there's 6.022 x 10^23 molecules of gas in 28g
28/6 = 4.7
so assuming you divide 6.022 x 10^23 by 4.7 to get the number of molecules of gas in 6g? So 1.3 x 10^23?
yep! be careful of rounding errors, you should have 1.29*10^23.
I did (6/28)*(6.02*10^23) but if your way makes sense to you then stick with that

so how many protons in 1.3*10^23?
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Thread starter 2 years ago
#7
only thing I can think of is 1.29 x 10^23 x 14? But I don't really understand why that is
(Original post by sotor)
yep! be careful of rounding errors, you should have 1.29*10^23.
I did (6/28)*(6.02*10^23) but if your way makes sense to you then stick with that

so how many protons in 1.3*10^23?
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2 years ago
#8
(Original post by anactualmess)
only thing I can think of is 1.29 x 10^23 x 14? But I don't really understand why that is
yep! if you have 14 protons in every molecule, then in 100 molecules you have 100x14 protons

and if you have 1.29*10^23 molecules, you get your answer

does that make sense?
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Thread starter 2 years ago
#9
ah okay thank you!
(Original post by sotor)
yep! if you have 14 protons in every molecule, then in 100 molecules you have 100x14 protons

and if you have 1.29*10^23 molecules, you get your answer

does that make sense?
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1 year ago
#10
first find the number of moles Mr(N2) = 14X2 = 28mass = 6.0gn(mol)= mass/Mr = 6/28 =Ans number of 1 proton = 6.022x10^23 x Ans = Ans2Nitrogen(N) has 7 protons where as N2 would have x2 = 14total protons in N2 gas 14 x Ans 2
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1 month ago
#11
1.) Work out moles of Nitrogen : 6g/14 = 0.42892.) Workout the number of particles by multiplying the moles by Avogadro's constant : 0.04289 x 6.022x10^23 = 2.58 x10^23.3.) Because there are 7 protons in each particle of N, multiply your anwser by 7 which give syou 1.8 x10^24.
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1 week ago
#12
(Original post by ZzZzZz121212)
1.) Work out moles of Nitrogen : 6g/14 = 0.42892.) Workout the number of particles by multiplying the moles by Avogadro's constant : 0.04289 x 6.022x10^23 = 2.58 x10^23.3.) Because there are 7 protons in each particle of N, multiply your anwser by 7 which give syou 1.8 x10^24.
Wouldn’t you multiply by 14 because it’s N2 so (7+7) = 14 protons
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2 minutes ago
#13
(Original post by Jaafar123)
Wouldn’t you multiply by 14 because it’s N2 so (7+7) = 14 protons
they worked out the moles of one atom of nitrogen so they did the protons per atom. I suggest doing it the other guy's way where you take into account it's diatomic and that you multiply it by 14 in the end
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