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Iceland88
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Eimmanuel
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For (a),
 K = \dfrac{ mv^2 }{2} = \dfrac{ m^2v^2 }{2m} = \dfrac{ p^2 }{2m}

For (b), you can use impulse = change in momentum
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Iceland88
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(Original post by Eimmanuel)
For (a),
 K = \dfrac{ mv^2 }{2} = \dfrac{ m^2v^2 }{2m} = \dfrac{ p^2 }{2m}

For (b), you can use impulse = change in momentum
For b there is no mass to find the velocity. So I divided the micro Newton by 9.81. I don’t think that’s correct
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Eimmanuel
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(Original post by Iceland88)
For b there is no mass to find the velocity. So I divided the micro Newton by 9.81. I don’t think that’s correct
I am not sure what you mean by there is no mass to find the velocity. You don’t need to find the velocity.

In your data-booklet, you should have the mass of the proton.
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