Electric Fields Calculation Specimen Paper 2 AQA Watch

mahmed69
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An α particle makes a head-on collision with a gold nucleus containing 79 protons. The distance of closest approach of the α particle to the nucleus is 4.0 × 10^−14 m.
What electrostatic force acts on the gold nucleus when at this separation?

A) 9.1 × 10^−11 N
B) 23 N
C) 290 N
D) 1.4 × 10^20 N
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justsomeguy17
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Use the equation for the force between two point charges, what are the charges on the nucleus and alpha particle?
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mahmed69
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yeah i did that, keep getting B which isn't right
(Original post by justsomeguy17)
Use the equation for the force between two point charges, what are the charges on the nucleus and alpha particle?
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homemadeclock
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post ur workings
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justsomeguy17
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23N is the correct answer, the mark scheme is wrong.
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mahmed69
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100% sure yeah?
my workings
F=(1/(4Pi*8.85x10^-12)) * (79x(1.6x10^-19)*2(1.6x10^-19)/(4x10^-14)^2)
=23N
(Original post by justsomeguy17)
23N is the correct answer, the mark scheme is wrong.
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justsomeguy17
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Yeah it's a specimen paper so they'll be a few mistakes. I've seen videos on youtube of people solving this question and they get the same answer 23N, I've also asked my physics teachers and they get 23N as well. Rest assured :P
(Original post by mahmed69)
100% sure yeah?
my workings
F=(1/(4Pi*8.85x10^-12)) * (79x(1.6x10^-19)*2(1.6x10^-19)/(4x10^-14)^2)
=23N
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mahmed69
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ah i seee i did the rest of the paper as well, some of the questions/answers are such nonsense. Just sums up AQA I guess

any predictions for tomorrow?
(Original post by justsomeguy17)
Yeah it's a specimen paper so they'll be a few mistakes. I've seen videos on youtube of people solving this question and they get the same answer 23N, I've also asked my physics teachers and they get 23N as well. Rest assured :P
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