Please help meeeee Watch

username4219164
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#1
Report Thread starter 4 weeks ago
#1
Can someone please explain how to work out this question??
Thank you so much

What is the mass, in mg, of carbon formed when 3.0 × 10−3 mol of propene undergoes
incomplete combustion?
2C3H6 + 3O2 → 6C + 6H2O

(Answer: 1.08 x 10^2)
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username4219164
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nvm everyone i worked it out lol hahah
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tiredofthisshi
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how did you work it out?
(Original post by sarahhhkh_)
nvm everyone i worked it out lol hahah
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username4219164
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There are 3x10-3 moles of propene so moles of carbon is 3 x 10-3 x3 (2:6 ratio) then use n=m/Mr to get mass in grams and then convert that to mg by x1000
(Original post by tiredofthisshi)
how did you work it out?
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