# Don't understand this sequences question

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#1
A pump is used to drain water from a hole on a building site. The pump can drain 10% of the water in the hole during one of its operation cycles. The volume of water in the hole at the start of the pumping process is 120m^3. Show that the total amount of water drained after n cycles is 120(1-0.9^n) m^3
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1 year ago
#2
Why not start by working back from the given answer to understand it?
What is the value when n=0, n=1, n=2, n=3? What do the different parts of the expression represent?
(Original post by student638274)
A pump is used to drain water from a hole on a building site. The pump can drain 10% of the water in the hole during one of its operation cycles. The volume of water in the hole at the start of the pumping process is 120m^3. Show that the total amount of water drained after n cycles is 120(1-0.9^n) m^3
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#3
So when n=0, 0 water is drained, n=1 12m3 is drained, when n=2 22.8m3 is drained. So the equation shows that as n (the no. of cycles) increases, the water drained also increases. But now I don't know what to do?
(Original post by mqb2766)
Why not start by working back from the given answer to understand it?
What is the value when n=0, n=1, n=2, n=3? What do the different parts of the expression represent?
0
1 year ago
#4
It would be less about the final answer, more the bits of the expression
n=0, 120*0
n=1 120*(1-0.9) = 120*0.1
n=2 120*(1-0.81) = 120*0.19

Which part is modelled by a geometric sequence and what is the sequence?

(Original post by student638274)
So when n=0, 0 water is drained, n=1 12m3 is drained, when n=2 22.8m3 is drained. So the equation shows that as n (the no. of cycles) increases, the water drained also increases. But now I don't know what to do?
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#5
I am still confused about the geometric sequence; the sequence is not being multiplied by a constant value of r if I'm not mistaken, or am I missing something?
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1 year ago
#6
(Original post by student638274)
I am still confused about the geometric sequence; the sequence is not being multiplied by a constant value of r if I'm not mistaken, or am I missing something?
if 10% is taken each time, what % of term one is left in term two? and term three?
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1 year ago
#7
Its slightly modified. If you expand the brackets you get

120 - 120*0.9^n

does that help? Draining 10% means 90% is left?

(Original post by student638274)
I am still confused about the geometric sequence; the sequence is not being multiplied by a constant value of r if I'm not mistaken, or am I missing something?
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#8
Would it mean 90% is left in the first one and in the second term aswell?
(Original post by sotor)
if 10% is taken each time, what % of term one is left in term two? and term three?
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#9
Yes it does, so when 10% of water is removed each time there will be 90% left, So to get this equation the initial amount of water is 120 and you subtract the volume of water remaining in the tank which is 120*0.9^n? If it is that how do you form the equation 120*0.9^n?
(Original post by mqb2766)
Its slightly modified. If you expand the brackets you get

120 - 120*0.9^n

does that help? Draining 10% means 90% is left?
0
1 year ago
#10
Sounds good.
(Original post by student638274)
Yes it does, so when 10% of water is removed each time there will be 90% left, So to get this equation the initial amount of water is 120 and you subtract the volume of water remaining in the tank which is 120*0.9^n? If it is that how do you form the equation 120*0.9^n?
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#11
Ah cheers, so this equation 120*0.9^n looks like it is a geometric sequence formula but isn't it layed out as un=ar^(n-1)? Why is it to the power of n in the equation that we formed instead of n-1? Also I was confused because the question seemed like it was asking for the total sum of water removed, which would imply it being a geometric series?
(Original post by mqb2766)
Sounds good.
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1 year ago
#12
0.9^(n-1) = 0.9^n * (1/0.9)
or
0.9^n = 0.9*0.9^(n-1)
They're the same - can both be used to represent the same geometric sequence, but with a slighly different initial values.
Generally, r^n is used when the initial value is at n=0 and r^(n-1) is used when the initial value is at n=1.
(Original post by student638274)
Ah cheers, so this equation 120*0.9^n looks like it is a geometric sequence formula but isn't it layed out as un=ar^(n-1)? Why is it to the power of n in the equation that we formed instead of n-1? Also I was confused because the question seemed like it was asking for the total sum of water removed, which would imply it being a geometric series?
Last edited by mqb2766; 1 year ago
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#13
What do you mean by slightly modified initial value? If I was going to prove that equation how would I get to 0.9^n divided by 0.9 because wouldn't that deviate from the initial formula that we are trying to prove 120(1-0.9^n)? Thanks.
(Original post by mqb2766)
0.9^(n-1) = 0.9^n * (1/0.9)
or
0.9^n = 0.9*0.9^(n-1)
They're the same, but a slighly modified initial value.
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#14
Just saw your edit, that makes sense. Just 1 thing to clear up: how do we know that to form this equation we use geometric sequences instead of geometric series?
(Original post by mqb2766)
0.9^(n-1) = 0.9^n * (1/0.9)
or
0.9^n = 0.9*0.9^(n-1)
They're the same - can both be used to represent the same geometric sequence, but with a slighly different initial values.
Generally, r^n is used when the initial value is at n=0 and r^(n-1) is used when the initial value is at n=1.
0
1 year ago
#15
I'd slightly modified the previous post. One initial value is 0.9 times or divided by the other so
a*0.9^n = (a*0.9)*0.9^(n-1)
They represent the same sequence, but there is a shift in "n" by one unit hence the "initial" term is shifted by one unit.

(Original post by student638274)
What do you mean by slightly modified initial value? If I was going to prove that equation how would I get to 0.9^n divided by 0.9 because wouldn't that deviate from the initial formula that we are trying to prove 120(1-0.9^n)? Thanks.
Last edited by mqb2766; 1 year ago
0
1 year ago
#16
A geometric series involves summing (integrating) previous (geometric) values. TBH, you could have done this question as a series where you modelled the amount removed as a sequence, but it would have been more complicated and probably easier to just do a simple sequence and simple algebra?
(Original post by student638274)
Just saw your edit, that makes sense. Just 1 thing to clear up: how do we know that to form this equation we use geometric sequences instead of geometric series?
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