# Don't understand this sequences question

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A pump is used to drain water from a hole on a building site. The pump can drain 10% of the water in the hole during one of its operation cycles. The volume of water in the hole at the start of the pumping process is 120m^3. Show that the total amount of water drained after n cycles is 120(1-0.9^n) m^3

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#2

Why not start by working back from the given answer to understand it?

What is the value when n=0, n=1, n=2, n=3? What do the different parts of the expression represent?

What is the value when n=0, n=1, n=2, n=3? What do the different parts of the expression represent?

(Original post by

A pump is used to drain water from a hole on a building site. The pump can drain 10% of the water in the hole during one of its operation cycles. The volume of water in the hole at the start of the pumping process is 120m^3. Show that the total amount of water drained after n cycles is 120(1-0.9^n) m^3

**student638274**)A pump is used to drain water from a hole on a building site. The pump can drain 10% of the water in the hole during one of its operation cycles. The volume of water in the hole at the start of the pumping process is 120m^3. Show that the total amount of water drained after n cycles is 120(1-0.9^n) m^3

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So when n=0, 0 water is drained, n=1 12m3 is drained, when n=2 22.8m3 is drained. So the equation shows that as n (the no. of cycles) increases, the water drained also increases. But now I don't know what to do?

(Original post by

Why not start by working back from the given answer to understand it?

What is the value when n=0, n=1, n=2, n=3? What do the different parts of the expression represent?

**mqb2766**)Why not start by working back from the given answer to understand it?

What is the value when n=0, n=1, n=2, n=3? What do the different parts of the expression represent?

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#4

It would be less about the final answer, more the bits of the expression

n=0, 120*0

n=1 120*(1-0.9) = 120*0.1

n=2 120*(1-0.81) = 120*0.19

Which part is modelled by a geometric sequence and what is the sequence?

n=0, 120*0

n=1 120*(1-0.9) = 120*0.1

n=2 120*(1-0.81) = 120*0.19

Which part is modelled by a geometric sequence and what is the sequence?

(Original post by

So when n=0, 0 water is drained, n=1 12m3 is drained, when n=2 22.8m3 is drained. So the equation shows that as n (the no. of cycles) increases, the water drained also increases. But now I don't know what to do?

**student638274**)So when n=0, 0 water is drained, n=1 12m3 is drained, when n=2 22.8m3 is drained. So the equation shows that as n (the no. of cycles) increases, the water drained also increases. But now I don't know what to do?

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I am still confused about the geometric sequence; the sequence is not being multiplied by a constant value of r if I'm not mistaken, or am I missing something?

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#6

(Original post by

I am still confused about the geometric sequence; the sequence is not being multiplied by a constant value of r if I'm not mistaken, or am I missing something?

**student638274**)I am still confused about the geometric sequence; the sequence is not being multiplied by a constant value of r if I'm not mistaken, or am I missing something?

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#7

Its slightly modified. If you expand the brackets you get

120 - 120*0.9^n

does that help? Draining 10% means 90% is left?

(Original post by

I am still confused about the geometric sequence; the sequence is not being multiplied by a constant value of r if I'm not mistaken, or am I missing something?

120 - 120*0.9^n

does that help? Draining 10% means 90% is left?

**student638274**)

I am still confused about the geometric sequence; the sequence is not being multiplied by a constant value of r if I'm not mistaken, or am I missing something?

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Would it mean 90% is left in the first one and in the second term aswell?

(Original post by

if 10% is taken each time, what % of term one is left in term two? and term three?

**sotor**)if 10% is taken each time, what % of term one is left in term two? and term three?

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Yes it does, so when 10% of water is removed each time there will be 90% left, So to get this equation the initial amount of water is 120 and you subtract the volume of water remaining in the tank which is 120*0.9^n? If it is that how do you form the equation 120*0.9^n?

(Original post by

Its slightly modified. If you expand the brackets you get

120 - 120*0.9^n

does that help? Draining 10% means 90% is left?

**mqb2766**)Its slightly modified. If you expand the brackets you get

120 - 120*0.9^n

does that help? Draining 10% means 90% is left?

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#10

Sounds good.

(Original post by

Yes it does, so when 10% of water is removed each time there will be 90% left, So to get this equation the initial amount of water is 120 and you subtract the volume of water remaining in the tank which is 120*0.9^n? If it is that how do you form the equation 120*0.9^n?

**student638274**)Yes it does, so when 10% of water is removed each time there will be 90% left, So to get this equation the initial amount of water is 120 and you subtract the volume of water remaining in the tank which is 120*0.9^n? If it is that how do you form the equation 120*0.9^n?

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Ah cheers, so this equation 120*0.9^n looks like it is a geometric sequence formula but isn't it layed out as un=ar^(n-1)? Why is it to the power of n in the equation that we formed instead of n-1? Also I was confused because the question seemed like it was asking for the total sum of water removed, which would imply it being a geometric series?

(Original post by

Sounds good.

**mqb2766**)Sounds good.

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#12

0.9^(n-1) = 0.9^n * (1/0.9)

or

0.9^n = 0.9*0.9^(n-1)

They're the same - can both be used to represent the same geometric sequence, but with a slighly different initial values.

Generally, r^n is used when the initial value is at n=0 and r^(n-1) is used when the initial value is at n=1.

or

0.9^n = 0.9*0.9^(n-1)

They're the same - can both be used to represent the same geometric sequence, but with a slighly different initial values.

Generally, r^n is used when the initial value is at n=0 and r^(n-1) is used when the initial value is at n=1.

(Original post by

Ah cheers, so this equation 120*0.9^n looks like it is a geometric sequence formula but isn't it layed out as un=ar^(n-1)? Why is it to the power of n in the equation that we formed instead of n-1? Also I was confused because the question seemed like it was asking for the total sum of water removed, which would imply it being a geometric series?

**student638274**)Ah cheers, so this equation 120*0.9^n looks like it is a geometric sequence formula but isn't it layed out as un=ar^(n-1)? Why is it to the power of n in the equation that we formed instead of n-1? Also I was confused because the question seemed like it was asking for the total sum of water removed, which would imply it being a geometric series?

Last edited by mqb2766; 1 year ago

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What do you mean by slightly modified initial value? If I was going to prove that equation how would I get to 0.9^n divided by 0.9 because wouldn't that deviate from the initial formula that we are trying to prove 120(1-0.9^n)? Thanks.

(Original post by

0.9^(n-1) = 0.9^n * (1/0.9)

or

0.9^n = 0.9*0.9^(n-1)

They're the same, but a slighly modified initial value.

**mqb2766**)0.9^(n-1) = 0.9^n * (1/0.9)

or

0.9^n = 0.9*0.9^(n-1)

They're the same, but a slighly modified initial value.

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Just saw your edit, that makes sense. Just 1 thing to clear up: how do we know that to form this equation we use geometric sequences instead of geometric series?

(Original post by

0.9^(n-1) = 0.9^n * (1/0.9)

or

0.9^n = 0.9*0.9^(n-1)

They're the same - can both be used to represent the same geometric sequence, but with a slighly different initial values.

Generally, r^n is used when the initial value is at n=0 and r^(n-1) is used when the initial value is at n=1.

**mqb2766**)0.9^(n-1) = 0.9^n * (1/0.9)

or

0.9^n = 0.9*0.9^(n-1)

They're the same - can both be used to represent the same geometric sequence, but with a slighly different initial values.

Generally, r^n is used when the initial value is at n=0 and r^(n-1) is used when the initial value is at n=1.

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#15

I'd slightly modified the previous post. One initial value is 0.9 times or divided by the other so

a*0.9^n = (a*0.9)*0.9^(n-1)

They represent the same sequence, but there is a shift in "n" by one unit hence the "initial" term is shifted by one unit.

a*0.9^n = (a*0.9)*0.9^(n-1)

They represent the same sequence, but there is a shift in "n" by one unit hence the "initial" term is shifted by one unit.

(Original post by

What do you mean by slightly modified initial value? If I was going to prove that equation how would I get to 0.9^n divided by 0.9 because wouldn't that deviate from the initial formula that we are trying to prove 120(1-0.9^n)? Thanks.

**student638274**)What do you mean by slightly modified initial value? If I was going to prove that equation how would I get to 0.9^n divided by 0.9 because wouldn't that deviate from the initial formula that we are trying to prove 120(1-0.9^n)? Thanks.

Last edited by mqb2766; 1 year ago

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#16

A geometric series involves summing (integrating) previous (geometric) values. TBH, you could have done this question as a series where you modelled the amount removed as a sequence, but it would have been more complicated and probably easier to just do a simple sequence and simple algebra?

(Original post by

Just saw your edit, that makes sense. Just 1 thing to clear up: how do we know that to form this equation we use geometric sequences instead of geometric series?

**student638274**)Just saw your edit, that makes sense. Just 1 thing to clear up: how do we know that to form this equation we use geometric sequences instead of geometric series?

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