M1 - review exercise question.

A particle of mass 0.3kg lies on a smooth plane inclined at an angle x to the horizontal, where tan x = 3/4. The particle is held in equilibrium by a horizontal force of magnitude Q newtons. The line of action of this force is in the same vertical plane as a line of greatest slope of the inclined plane. Calculate the value of Q, to one decimal place.

Is this diagram correct?
Do I need to include the frictional force in this question and if so which direction should it go?

Reply 1

Christophicus

18

Please. It's only a check question, not a do question.

Reply 2

SunGod

I'd move Q over to the left and have the arrow going into the particle, but thats me.

Reply 3

Christophicus

18

Does anyone else know?

Reply 4

The Chameleon

OP

I'm sorry, I don't get the question and don't even know where to start. Can someone help?

Reply 5

The Chameleon

OP

Do I include the frictional force if the particle is in equilibrium as the question states?

Reply 6

username9816

14

The Chameleon

Do I include the frictional force if the particle is in equilibrium as the question states?

1.) "The line of action of this force is in the same vertical plane as a line of greatest slope of the inclined plane." - I don't understand what this means, otherwise could answer your Q.

2.) No, the plane is smooth so there is no friction.

Reply 7

The Chameleon

OP

Invisible

1.) "The line of action of this force is in the same vertical plane as a line of greatest slope of the inclined plane." - I don't understand what this means, otherwise could answer your Q.

2.) No, the plane is smooth so there is no friction.

I think that what 1 means is that the direction of Q is above the vertical plane, ie to the left but I could be wrong.

Reply 8

username9816

14

The Chameleon

A particle of mass 0.3kg lies on a smooth plane inclined at an angle x to the horizontal, where tan x = 3/4. The particle is held in equilibrium by a horizontal force of magnitude Q newtons. The line of action of this force is in the same vertical plane as a line of greatest slope of the inclined plane. Calculate the value of Q, to one decimal place.

Is this diagram correct?
Do I need to include the frictional force in this question and if so which direction should it go?

I'm going to presume here that the force Q is acting upwards, parallel to the plane, which makes sense as it would then balance the opposing weight component of the particle, causing it to be in equilibrium.

x = tan^-1(3/4) = 36.87 degrees.

Resolving Parallel to the plane:

Q = mgsinx = 0.3 * 9.8 * sin36.87
---> Q = 1.8 N (1.D.P)

M1 - review exercise question.

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