dvbuosnklmkoi888
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Hydrogen fuel cells generate energy from redox reactions. Hydrogen fuel cells have been
developed to operate in either an acidic or alkaline electrolyte.
Standard electrode potentials for several redox systems are shown below.
2H2O(l) + 2e– 2OH–(aq) + H2(g) Eө = –0.83V
2H+(aq) + 2e– H2(g) Eө = 0.00V
O2(g) + 2H2O(l) + 4e– 4OH–(aq) Eө = +0.40V
O2(g) + 4H+(aq) + 4e– 2H2O(l) Eө = +1.23V
Using this information, show how acidic and alkaline hydrogen fuel cells produce the same
overall cell equation and cell potential, despite different reactions taking place at each
electrode.

how do you know which ones are alkaline and which are acidic ...
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nj1234
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acidic uses h+ and h2o to balance but alkaline ones use oh- and h2o to balance
(Original post by dvbuosnklmkoi888)
Hydrogen fuel cells generate energy from redox reactions. Hydrogen fuel cells have been
developed to operate in either an acidic or alkaline electrolyte.
Standard electrode potentials for several redox systems are shown below.
2H2O(l) + 2e– 2OH–(aq) + H2(g) Eө = –0.83V
2H+(aq) + 2e– H2(g) Eө = 0.00V
O2(g) + 2H2O(l) + 4e– 4OH–(aq) Eө = +0.40V
O2(g) + 4H+(aq) + 4e– 2H2O(l) Eө = +1.23V
Using this information, show how acidic and alkaline hydrogen fuel cells produce the same
overall cell equation and cell potential, despite different reactions taking place at each
electrode.

how do you know which ones are alkaline and which are acidic ...
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ajmartin8
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Acid = H+ electrolyte, alkali = OH- electrolyte

When you add both half-cell reactions with H+, or both with OH- you get the same overall equation of 2H2(g) + O2(g) -> 2H2O(l) with a cell potential of +1.23V in both cases
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dvbuosnklmkoi888
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thanks
(Original post by nj1234)
acidic uses h+ and h2o to balance but alkaline ones use oh- and h2o to balance
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dvbuosnklmkoi888
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thanks
(Original post by ajmartin8)
Acid = H+ electrolyte, alkali = OH- electrolyte

When you add both half-cell reactions with H+, or both with OH- you get the same overall equation of 2H2(g) + O2(g) -> 2H2O(l) with a cell potential of +1.23V in both cases
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