MMA-Medic
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If anyone is struggling with their chemistry revision, or needs some tips on how to revise, feel free to ask in this thread or pm me (AQA spec only though)

I am an AQA chemistry tutor, and I understand that exams are approaching so I’m offering help to anyone who needs it
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dedfghjkl
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(Original post by MMA-Medic)
If anyone is struggling with their chemistry revision, or needs some tips on how to revise, feel free to ask in this thread or pm me (AQA spec only though)

I am an AQA chemistry tutor, and I understand that exams are approaching so I’m offering help to anyone who needs it
can you explain bon harbor process to mea
i always get confused becuase in the formarion so stuff is halved or doubled
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MMA-Medic
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(Original post by dedfghjkl)
can you explain bon harbor process to mea
i always get confused becuase in the formarion so stuff is halved or doubled
what part of the born-Haber cycles do you want me to explain? All of it or just a few parts?
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dedfghjkl
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the whole thing would be great please
(Original post by MMA-Medic)
what part of the born-Haber cycles do you want me to explain? All of it or just a few parts?
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MMA-Medic
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(Original post by dedfghjkl)
the whole thing would be great please
Sure, I will pm you
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hm061
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how about aqua metal ions the inorganic chapter pls
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MMA-Medic
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(Original post by hm061)
how about aqua metal ions the inorganic chapter pls
Send me you’re email address, I will send u a document that should help you out slightly
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dyfugikholjp
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(Original post by MMA-Medic)
Send me you’re email address, I will send u a document that should help you out slightly
friend i need your help
do you know how to calculate relative molecular mass of this question
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UnknownError404
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(Original post by dyfugikholjp)
friend i need your help
do you know how to calculate relative molecular mass of this question
you've been given time and distance so you can use speed=distance/time to calculate speed of the ion.

speed is v
so you now have k.e(given to you) and v(calculated) so use k.e =1/2mv² to calculate mass.

this mass is mass of one ion in kg so you times by 1000 to convert to grams and then you times by avogadros constant to work out mr.

you use avogadros constant because the mass you worked out from the k.e equation is the mass of one ion however mr is the mass of one mole of that atom or ion.
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dyfugikholjp
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(Original post by UnknownError404)
you've been given time and distance so you can use speed=distance/time to calculate speed of the ion.

speed is v
so you now have k.e(given to you) and v(calculated) so use k.e =1/2mv² to calculate mass.

this mass is mass of one ion in kg so you times by 1000 to convert to grams and then you times by avogadros constant to work out mr.

you use avogadros constant because the mass you worked out from the k.e equation is the mass of one ion however mr is the mass of one mole of that atom or ion.
[QUOTE=dyfugikholjp]you said reranging =
speed=distance/time to calculate speed of the ion.
so is the distance is 1.50m
and the time is 1.23 x 10-5
so is the speed 1.50/1.23 x 10-5 =121951.2195V
so use k.e =1/2mv² to calculate mass.
help i am confused
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dyfugikholjp
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is there anyone that can help me with this question i am really confused
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MMA-Medic
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yeah this is right. Then once you have worked out mass, you need to multiply it by 1000 because you have been given the mass in Kg in the question and you want g. the mass you have worked out in the KE formula is the mass of one ion, and Mr/avogadros constant = mass of one atom/ion. sou you rearrange this to work out the Mr by multiplying the mass of the single ion with avogadros constant

hope this helps
(Original post by dyfugikholjp)
(Original post by dyfugikholjp;undefined)
you said reranging =
speed=distance/time to calculate speed of the ion.
so is the distance is 1.50m
and the time is 1.23 x 10-5
so is the speed 1.50/1.23 x 10-5 =121951.2195V
so use k.e =1/2mv² to calculate mass.
help i am confused
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dyfugikholjp
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ho
(Original post by MMA-Medic)
yeah this is right. Then once you have worked out mass, you need to multiply it by 1000 because you have been given the mass in Kg in the question and you want g. the mass you have worked out in the KE formula is the mass of one ion, and Mr/avogadros constant = mass of one atom/ion. sou you rearrange this to work out the Mr by multiplying the mass of the single ion with avogadros constant

hope this helps
how do i calculate mass
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MMA-Medic
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rearrange the KE formula so m = KE/0.5v^2
(Original post by dyfugikholjp)
ho

how do i calculate mass
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dyfugikholjp
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ok i got that thanks
(Original post by MMA-Medic)
rearrange the KE formula so m = KE/0.5v^2
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dyfugikholjp
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for this question is this the answer the enthalpy of lattice formation for ceasium iodide in table 1 is a value obtained by experiment.the values obtained by calculation using perfect ionic model is -582deduce what these valuse indicate about caesium iodide



close to perfectly ionic as possible - as showcased by the very small difference between the two values. close to perfectly ionic as possible - as showcased by the very small difference between the two values.
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MMA-Medic
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yeah so if the experimental value is equal to or close to the theoretical value, then the molecule is perfectly ionic and consists of perfect spheres. If the values are different, then it contains covalent character
(Original post by dyfugikholjp)
for this question is this the answer the enthalpy of lattice formation for ceasium iodide in table 1 is a value obtained by experiment.the values obtained by calculation using perfect ionic model is -582deduce what these valuse indicate about caesium iodide



close to perfectly ionic as possible - as showcased by the very small difference between the two values. close to perfectly ionic as possible - as showcased by the very small difference between the two values.
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dyfugikholjp
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(Original post by MMA-Medic)
yeah so if the experimental value is equal to or close to the theoretical value, then the molecule is perfectly ionic and consists of perfect spheres. If the values are different, then it contains covalent character
so i wont get the mark for saying
close to perfectly ionic as possible
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MMA-Medic
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with what you're telling me, i think you will, because you are implying that it has no covalent character
(Original post by dyfugikholjp)
so i wont get the mark for saying
close to perfectly ionic as possible
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dyfugikholjp
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and for the question that asks the meaning of the term periodicity can i say trends in element properties with increasing atomic number
and get full marks
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