maths y-coordinate of minimumWatch

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#1
Hey guys,
so I'm stuck, any help please???
0
2 weeks ago
#2
(Original post by mikaelalrc)
Hey guys,
so I'm stuck, any help please???
Could you post the question?
0
#3
Oh ye messed up, sorry!

g(x) = x^3 + kx^2 - 15x + 5
g'(x) = 3x^2 + 2kx - 15
tangent to the graph of y = g(x) at x=2 is parallel to the line y= 21x + 7
m = 21
k = 6
g'(-1) = -24
g is decreasing at x= -24 as it is negative

Find the y-coordinate of the local minimum.

(Original post by Muttley79)
Could you post the question?
0
2 weeks ago
#4
(Original post by mikaelalrc)
Oh ye messed up, sorry!

g(x) = x^3 + kx^2 - 15x + 5
g'(x) = 3x^2 + 2kx - 15
tangent to the graph of y = g(x) at x=2 is parallel to the line y= 21x + 7
m = 21
k = 6
g'(-1) = -24
g is decreasing at x= -24 as it is negative

Find the y-coordinate of the local minimum.
Isn't there another thread on this? I think you've sorted it now.
0
#5
kind of, yes. thank you anyway!
(Original post by Muttley79)
Isn't there another thread on this? I think you've sorted it now.
0
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