Canes Arslan
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#1
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X^X! What was that?!? I tried solving it by taking the exponentials of both sides but idk if i found the right answer! Also how did you guys find the paper?
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dont know it
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(Original post by Canes Arslan)
X^X! What was that?!? I tried solving it by taking the exponentials of both sides but idk if i found the right answer! Also how did you guys find the paper?
I got x=e^-1 but I don't think that's right.
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DynestiGTI
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that's right
(Original post by dont know it)
I got x=e^-1 but I don't think that's right.
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Personal_17
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(Original post by DynestiGTI)
that's right
Yayy I got that as well
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Plinking
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#5
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I think it is correct
(Original post by dont know it)
I got x=e^-1 but I don't think that's right.
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Pmk671
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How did you get that?
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MaterialDesign
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#7
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I got
f'(x)=x^x

= x^x(1+ lnx)
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dont know it
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#8
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(Original post by Pmk671)
How did you get that?
y=x^x

ln(y)=xln(x)

Implicitly differentiate: 1/y dy/dx = 1+ln(x)

dy/dx = y(1+ln(x))

0 = x^x (1+ln(x))

1+ln(x)=0

ln(x)=-1

e^ln(x) = e^-1

x=e^-1
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Pmk671
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Any other answers?
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