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Aqa a-level biology 7402 - paper 2 - unofficial mark scheme 13th June 2019
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Drop down any questions and answers from the test and I will produce an unofficial mark scheme based on most popular answers, thanks!
- Describe Succession-
How an ecosystem changes over time (change in species diversity and habitat diversity) – relies on environment being made less hostile by present species via death and decomposition leading to it being outcompeted and replaced by larger better adapted species.
- Percentage question (3sf)
- KJmy calculation question
-Hardy-Weinburg Calculation-
48%
- Describe Succession-
How an ecosystem changes over time (change in species diversity and habitat diversity) – relies on environment being made less hostile by present species via death and decomposition leading to it being outcompeted and replaced by larger better adapted species.
- Percentage question (3sf)
- KJmy calculation question
-Hardy-Weinburg Calculation-
48%
Last edited by RAKH000; 1 year ago
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#2
That hardy weinberg q- Me and my mates got 32% but people got like 46% or something?
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I also got 46% too.
(Original post by Zxr_)
That hardy weinberg q- Me and my mates got 32% but people got like 46% or something?
That hardy weinberg q- Me and my mates got 32% but people got like 46% or something?
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What did you get for the calculation for KJmy and the percentage question, it was two of the first few questions.
(Original post by Zxr_)
That hardy weinberg q- Me and my mates got 32% but people got like 46% or something?
That hardy weinberg q- Me and my mates got 32% but people got like 46% or something?
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How did you get 0.155 for the percentage?
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#8
I multiplied all the percentages together
(Original post by RAKH000)
How did you get 0.155 for the percentage?
How did you get 0.155 for the percentage?
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(Original post by The Anarchist7)
I got 48 percent
I got 48 percent
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#10
(Original post by RAKH000)
How did you get 0.155 for the percentage?
How did you get 0.155 for the percentage?
I worked it out by dividing 2.1 by 100, then multiplying by 12.7 = 0.2667. Then dividing 0.2667 by 100 and multiplying by 58.
Last edited by 1Secord; 1 year ago
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#12
0.36= q^2 or recessive
q= 0.6
P must be 0.4 so p^2 = 0.16 ( number of homozygous dominant)
Therefore, 2pq =
0.64 - 0.16 = 0.48
48 percent WAS the answer can’t see how 0.46 was right unless some one can explain otherwise
q= 0.6
P must be 0.4 so p^2 = 0.16 ( number of homozygous dominant)
Therefore, 2pq =
0.64 - 0.16 = 0.48
48 percent WAS the answer can’t see how 0.46 was right unless some one can explain otherwise
(Original post by The Anarchist7)
I got 48 percent
I got 48 percent
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#13
(Original post by Zxr_)
That hardy weinberg q- Me and my mates got 32% but people got like 46% or something?
That hardy weinberg q- Me and my mates got 32% but people got like 46% or something?
If it is wrong we would still get marks for multiplying 2 by two other numbers.
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Yeah thats exactly what I did, think I got the final value confused. Must've been 48 percent if those values are correct.
(Original post by The Anarchist7)
0.36= q^2 or recessive
q= 0.6
P must be 0.4 so p^2 = 0.16 ( number of homozygous dominant)
Therefore, 2pq =
0.64 - 0.16 = 0.48
48 percent WAS the answer can’t see how 0.46 was right unless some one can explain otherwise
0.36= q^2 or recessive
q= 0.6
P must be 0.4 so p^2 = 0.16 ( number of homozygous dominant)
Therefore, 2pq =
0.64 - 0.16 = 0.48
48 percent WAS the answer can’t see how 0.46 was right unless some one can explain otherwise
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#15
Probs not seeing as you didn’t have to multiple anything by 2 to work out the answer
(Original post by namelessfeelsx)
I got 32% as well... because dominant homozygous would be p^2 so p=0.8 (after square rooting 0.64), then 1-0.8=0.2, then 2pq= 2x0.8x0.2= 0.32
If it is wrong we would still get marks for multiplying 2 by two other numbers.
I got 32% as well... because dominant homozygous would be p^2 so p=0.8 (after square rooting 0.64), then 1-0.8=0.2, then 2pq= 2x0.8x0.2= 0.32
If it is wrong we would still get marks for multiplying 2 by two other numbers.
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Did you the other percentage question where you had to put it to 3sf?
(Original post by The Anarchist7)
0.36= q^2 or recessive
q= 0.6
P must be 0.4 so p^2 = 0.16 ( number of homozygous dominant)
Therefore, 2pq =
0.64 - 0.16 = 0.48
48 percent WAS the answer can’t see how 0.46 was right unless some one can explain otherwise
0.36= q^2 or recessive
q= 0.6
P must be 0.4 so p^2 = 0.16 ( number of homozygous dominant)
Therefore, 2pq =
0.64 - 0.16 = 0.48
48 percent WAS the answer can’t see how 0.46 was right unless some one can explain otherwise
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#17
(Original post by The Anarchist7)
0.36= q^2 or recessive
q= 0.6
P must be 0.4 so p^2 = 0.16 ( number of homozygous dominant)
Therefore, 2pq =
0.64 - 0.16 = 0.48
48 percent WAS the answer can’t see how 0.46 was right unless some one can explain otherwise
0.36= q^2 or recessive
q= 0.6
P must be 0.4 so p^2 = 0.16 ( number of homozygous dominant)
Therefore, 2pq =
0.64 - 0.16 = 0.48
48 percent WAS the answer can’t see how 0.46 was right unless some one can explain otherwise
I did 1-0.64 = 0.36 - So 36% must be black body, gg.
Square root of 0.36 = 0.6.
1 - 0.6 = 0.4 ( Since 1 = p + q )
The question asked for heterozygous - 2*p*q
2 * 0.6 * 0.4 = 0.48 = 48%
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#18
(Original post by mcsqaured)
I got the same as that but my Rf value was 0.60
I got the same as that but my Rf value was 0.60
(Original post by RAKH000)
How did you get 0.155 for the percentage?
How did you get 0.155 for the percentage?
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#19
If for the sampling questions i talked about both quadrats and transects would i get 0 marks, it didn’t say state one method?
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#20
I remember there was a question asking about photoionisation. ( 2 marks?)
Another question about how to estimate the population of sundews, a type of insect eating plant, in a marshy bog area. ( 5 marks )
The second part to this question was asking why it is beneficial to the sundews to eat insects when there is a low concentration of nutrients in the soil ( 2 marks ?)
There was another question about calculating the volume of distilled water and the concentrated IAA solution to make 40cm^3 of the solution with a concentration of 10 parts per million? ( I really can't remember the question that well, I just know I struggled with it )
Another question about how to estimate the population of sundews, a type of insect eating plant, in a marshy bog area. ( 5 marks )
The second part to this question was asking why it is beneficial to the sundews to eat insects when there is a low concentration of nutrients in the soil ( 2 marks ?)
There was another question about calculating the volume of distilled water and the concentrated IAA solution to make 40cm^3 of the solution with a concentration of 10 parts per million? ( I really can't remember the question that well, I just know I struggled with it )
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