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OCR MEI B 2019 paper 3 14TH June Unofficial MS

soon to be updated


Well that was shyte

functions question
draw graph
y=(x+2)/3
and y=3x-2

Partial fractions
1/(x+2) -1(x+3)
Integral of the above is ln (x+2/x+3)+c

for f(x)>f-1(x)
x>1
e question
Dy/dx gives e^x/(1e^x)^2 so both numerator and denominator always positive hence increasing function

Area of triangle
2/3 units^2

Turning point is (-4,-23)
Translation was also (-4 -23)

Proofs
Multiply all values add 1
If this number is prime then it is not in the list
If it isn’t prime then it has to have a prime factor which is also a factor of 1
That is impossible hence contradiction so there is no largest prime

Circle question.
Radius was 4
Centre (10,4)
Set x=circle equation
No real roots as can’t square root negative

Implicit question
the values were on y axis I think
(0, rt8) (0, -rt8)

Integration question
Loads of (1+rootx) terms then ln(1+rootx) + c

Comprehension was clapped so cba to type that out

@Evil Homernh
(edited 4 years ago)

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I did like 2 marks max of the comp
Reply 2
How did people find the paper 3... ?
Reply 3

Spoiler



Original post by Samwell88
I did like 2 marks max of the comp
Reply 4
Pure was good comp was ugly
Original post by a1ba1
How did people find the paper 3... ?
1. F-1(x)=(x+2)/3
2 lines reflected in y=x
X>1
2. Translate vector (-4,-23)
Minimum (-4,-23)
3. 1/(x+2)-1/(x+3)
Ln(x+2/x+3) +c
4.rationalise each and compare Lhs and rhs which both simplified to roo13 - root10
5. Infinity of primes proof
6. (X-10)^2+(y-4)^2=16
Solve pair of equations to get
Y^2-14y+50=0
Negative discriminate hence no intersections
(5,2) vector
7. 6(ln3)^3
8 2/3 3/4
9. (0,root8),(0,-root8)
10. e^x/(1+e^x)^2 > 0 therefore increasing
11. 2/3(u)^3-3(u)^2+6(u)-2lnu +c sub back u obvs
(edited 4 years ago)
Genuinely liked that paper a lot.
Can someone make a poll for it
Original post by beditness
Genuinely liked that paper a lot.


I agree. It was great fun! OCR really did give us a treat this yr ay!
Yeah it was sooo good!! Literally had an hour to check and the questions just synced you know
first time I've managed to answer every comprehension question
Not sure why but I really liked that paper. Realising one or two small careless mistakes now, and couldn't do the proof, but was otherwise really good. Hope it makes up for the atrocious stats paper :frown:
Grade boundary predictions for the whole 3 papers?
Original post by beditness
Grade boundary predictions for the whole 3 papers?

A* around 80-83%
Reply 14
Wouldn’t the translation of the curve be positive 4 and -23 because it’s x-4=0 .
Nop its -4
Original post by m22r
Wouldn’t the translation of the curve be positive 4 and -23 because it’s x-4=0 .
Reply 16
Did anyone else get 1/12 for the area of the curve bounded by the tangent?
I got 3/4. I integrated the x=y^1/3 get the area of y, then use the triangle to take away that area to get it
Original post by m22r
Did anyone else get 1/12 for the area of the curve bounded by the tangent?
What % would a B be?
Original post by MrMoment
A* around 80-83%
Reply 19
Oh :frown: I just integrated y=x^3 to get 1/4x^4 then sub in 1 to get 1/4. Then took it away from the area of the little triangle which I got was 1/6 so I got 1/12.
Original post by Evergarden
I got 3/4. I integrated the x=y^1/3 get the area of y, then use the triangle to take away that area to get it

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