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    Hi, i did a maths module last year (its out of 72). i got 95/100 UMS and i looked at the examiners report and the grade boundary for an A was 54/72 which gave 72/100 UMS marks. from this information is it possible to calculate what raw mark i got? thanks

    EDIT: gives 80/100 UMS not 72/100
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    (Original post by Quantum*)
    Hi, i did a maths module last year (its out of 72). i got 95/100 UMS and i looked at the examiners report and the grade boundary for an A was 54/72 which gave 72/100 UMS marks. from this information is it possible to calculate what raw mark i got? thanks
    At my calculations that works out at approximately 68 out of 72
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    thanks, could you tell me how you worked it out?
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    What was the gap between grade boundaries (UMS)?
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    54/72 was an A - 80 UMS
    47/72 for a B - 70
    40/72 for a C - 60

    SORRY I MEANT 54/72 GAVE 80 UMS NOT 72
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    I calculate it to be 64.5, so it'd round to 65.

    I solved \dfrac{x-54}{14} \times 20 + 80 = 95, (a number x along the top boundary divided by the width of the top boundary converted to the width of the UMS boundary added to the bottom of the UMS boundary = 95.
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    (Original post by Quantum*)
    54/72 was an A - 80 UMS
    47/72 for a B - 70
    40/72 for a C - 60

    SORRY I MEANT 54/72 GAVE 80 UMS NOT 72

    Well

    x/72=95/100

    so (95 x 72)/100 will give your raw mark.. that's just a rough trick though, don't quote me directly lol.
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    (Original post by Glutamic Acid)
    I calculate it to be 64.5, so it'd round to 65.

    I solved \dfrac{x-54}{14} \times 20 + 80 = 95, (a number x along the top boundary divided by the width of the top boundary converted to the width of the UMS boundary added to the bottom of the UMS boundary = 95.
    Well, this thing seems a lot more technical! Haha, so much for my little rearranging! :rolleyes:
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    (Original post by amywalters)
    Well, this thing seems a lot more technical! Haha, so much for my little rearranging! :rolleyes:
    What makes it more technical is that there's a "cap". A mark where anything above gets 100% UMS, and this is equal to 2 * (raw mark boundary width) + (raw mark boundary for A).
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    (Original post by Glutamic Acid)
    What makes it more technical is that there's a "cap". A mark where anything above gets 100% UMS, and this is equal to 2 * (raw mark boundary width) + (raw mark boundary for A).
    Ah I see, well I was close, I'm a psychologist not a mathmatician :p:
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    thanks that seems to be more like that mark i would have thought i got.

    does this formula work for any module/subject?. replacing everything but the 14 and 20 stay the same right?
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    (Original post by Quantum*)
    thanks that seems to be more like that mark i would have thought i got.

    does this formula work for any module/subject?. replacing everything but the 14 and 20 stay the same right?
    It won't, because the gap between raw mark boundaries will depend on an individual paper, and the gap between UMS boundaries will depend on the module.
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    (Original post by Glutamic Acid)
    What makes it more technical is that there's a "cap". A mark where anything above gets 100% UMS, and this is equal to 2 * (raw mark boundary width) + (raw mark boundary for A).
    What about in the instance where the grade boundaries are raised so that there is less than 2 grade boundary widths above the A boundary. For example, 60/72 being an A and a grade boundary width of 8.
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    (Original post by Kerch)
    What about in the instance where the grade boundaries are raised so that there is less than 2 grade boundary widths above the A boundary. For example, 60/72 being an A and a grade boundary width of 8.
    My instinct is that 72 (full raw marks) would count as the upper boundary, but I can't say for certain. The whole UMS <==> raw marks thing is explained on the AQA website somewhere.
 
 
 

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