maths Watch

mckenzie12345
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#1
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#1
1. 5x/2 +1 =10
2. 2x/7 -- 3 = 2
what do I need to do next
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JackMoseley
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#2
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#2
I would change the - - to a +

Multiply out the fractions (1. x 2, 2. x 7) - remember to multiply both sides.

Make the x coefficients the same and then solve like normal simultaneous equations
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mckenzie12345
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#3
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#3
1. times two by what
2. times 7 by what
(Original post by JackMoseley)
I would change the - - to a +

Multiply out the fractions (1. x 2, 2. x 7) - remember to multiply both sides.

Make the x coefficients the same and then solve like normal simultaneous equations
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JackMoseley
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#4
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(Original post by mckenzie12345)
1. times two by what
2. times 7 by what
So the first equation (5x/2 + 1 = 10) multiply it by 2
The second equation (2x/7 + 3 = 2) multiply it by 7
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JJJJJAAAAMES
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(Original post by mckenzie12345)
1. 5x/2 +1 =10
2. 2x/7 -- 3 = 2
what do I need to do next
What are you trying to do?

Are they separate questions?
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mckenzie12345
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#6
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#6
ok thanks
(Original post by JackMoseley)
So the first equation (5x/2 + 1 = 10) multiply it by 2
The second equation (2x/7 + 3 = 2) multiply it by 7
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mckenzie12345
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#7
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#7
1. 5x/2 + 1 = 11 then times 2 and 5 x 2 =10
2. 2x/7 - 3 = 2 then times 7 and 2 x 7 =14
what should I do next

(Original post by mckenzie12345)
ok thanks
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mckenzie12345
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#8
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#8
yes don't worry
(Original post by JJJJJAAAAMES)
What are you trying to do?

Are they separate questions?
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mckenzie12345
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#9
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#9
help
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JackMoseley
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#10
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(Original post by mckenzie12345)
help
Just solve from there:

5x + 2 = 20
2x + 21 = 14
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mckenzie12345
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#11
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#11
hi what do you mean

(Original post by JackMoseley)
Just solve from there:

5x + 2 = 20
2x + 21 = 14
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JackMoseley
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#12
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#12
(Original post by mckenzie12345)
hi what do you mean
Name:  59339605-2114-44BF-A3AA-0681645F47A4.jpg.jpeg
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JackMoseley
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#13
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(Original post by mckenzie12345)
hi what do you mean
Name:  19126228-8A9F-4FF2-AC29-E8447C9F4FE6.jpg.jpeg
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The or on both questions is just another way you could work it out
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mckenzie12345
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#14
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#14
its keeps saying wrong answer for both

(Original post by mckenzie12345)
hi what do you mean
(Original post by JackMoseley)
Name:  19126228-8A9F-4FF2-AC29-E8447C9F4FE6.jpg.jpeg
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The or on both questions is just another way you could work it out
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JackMoseley
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#15
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(Original post by mckenzie12345)
its keeps saying wrong answer for both
Hmm, assuming that the equations are separate, this is correct?

are these equations linked in any way or are they separate questions?
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mckenzie12345
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#16
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#16
they are separate questions
(Original post by JackMoseley)
Hmm, assuming that the equations are separate, this is correct?

are these equations linked in any way or are they separate questions?
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JackMoseley
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#17
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#17
(Original post by mckenzie12345)
they are separate questions
Does it give you a correct answer?
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mckenzie12345
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#18
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#18
no it just said wrong answer
(Original post by JackMoseley)
Does it give you a correct answer?
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JackMoseley
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#19
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#19
(Original post by mckenzie12345)
no it just said wrong answer
Not sure... I’ve subbed this into my calculator which will solve algebra and it’s what it’s getting.

It’s saying that
1. x= 3.6
2. x = -3.5
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mckenzie12345
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#20
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#20
but it keeps saying wrong answer for both
(Original post by JackMoseley)
Not sure... I’ve subbed this into my calculator which will solve algebra and it’s what it’s getting.

It’s saying that
1. x= 3.6
2. x = -3.5
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