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Hi there!, a bit of a doubt here!

This might be a simple to solve;
I dont get how, in part cii), how the 2theta-1.107 =3pi . i dont really know where the value of 3pi comes from. If someone could explain to me fast it would be much appreciated! I have C34 IAL exam on the 18 btw hahah
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Reply 1
Avatar for mqb2766
mqb2766
21
You're looking for sin()=0 as this will produce a maximum, so 0, pi, 2pi, 3pi ...
Theta needs to satisfy 0..2pi and you're asked for the largest value.
@mqb2766
0, pi, 2pi, 3pi , its these values because its 2theta right??
Ok what a silly mistake hahahah, thank you anyways!!
Reply 3
Avatar for mqb2766
mqb2766
21
Sin(0) = sin(pi) = sin(2pi) = ....
Its where the denominator is the minimum, hence equate the argument and find theta.
Original post by franjimenezn17
@mqb2766
0, pi, 2pi, 3pi , its these values because its 2theta right??
Ok what a silly mistake hahahah, thank you anyways!!
@mqb2766 perfect, got it, thanks very much!!

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