Turn on thread page Beta
    • Thread Starter
    Offline

    0
    ReputationRep:
    There was this question that asked me to work out the decay constant of a subtance which has a half life of 2.6 years. I used the equation k=In2/Half life

    The question also gave me the information that 1 year is equal to 3.15 * 10^7 seconds. I basically set the equation out like this:

    k = In2/ 2.6 * 3.15 * 10^7

    According to the mark scheme this was supposed to be the correct way to set out the answer and for it the value of k (the decay constant) came to 0.46 * 10^-9 . Now, the mark scheme stated that the correct answer should be 8.6 * 10^-9 . So now I'm wondering is the mark scheme wrong or is it possible that the fault lies rather in my calculator.
    Offline

    0
    ReputationRep:
    Hm. I got 8.5 * 10^-9 when I did it.

    Have you checked it and made sure you'd got brackets in the right place and everything?

    Edit: Sorry, did you mean 0.46 or 8.46? 'Cause if you mean the latter I got the same.
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: June 9, 2008

University open days

  • Heriot-Watt University
    School of Textiles and Design Undergraduate
    Fri, 16 Nov '18
  • University of Roehampton
    All departments Undergraduate
    Sat, 17 Nov '18
  • Edge Hill University
    Faculty of Health and Social Care Undergraduate
    Sat, 17 Nov '18
Poll
Have you ever experienced bullying?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.