Itsnotaphasemom
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I have been struggling with this for a while.
I know for part a) it’s B (inert gases are most stable). Part b) and c) really stumped me.
The correct answers say b) is A and c) is D.

Can anyone explain?
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Hazelly
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Hello! the attachment hasn't loaded properly I'm afraid.
(Original post by Itsnotaphasemom)
Attachment 834898

I have been struggling with this for a while.
I know for part a) it’s B (inert gases are most stable). Part b) and c) really stumped me.
The correct answers say b) is A and c) is D.

Can anyone explain?
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Itsnotaphasemom
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(Original post by Hazzabear)
Hello! the attachment hasn't loaded properly I'm afraid.
Ahhh!
I’ll type it out instead:

Question 22)
The first ionisation energies, in kj mol, of 4 elements with consecutive atomic numbers are shown below.
A) 1680
B) 2080
C) 496
D) 738

a) which element could be an inert gas?
b) which element could be X in a covalent compount with formula HX?
c) which element could be Y in an ionic compound with formula YH2?
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Boss_Rhythm
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Alright so if you know that B is obviously an inert gas then the rest is easy

A) is Group 7
B) is group 8
C) is group 1
D) is group 2

covalent compound with HX means that 1 electron is shared and it fulfills the outer layer of both elements so it has to be group 7 to fulfill that requirement as it can't be group 1 as then it would form a ionic bond
SO Group 7 element will be before the Group 8 inert gas so it must be A since the ionisation energies are consecutive

Then now that you know that the next one is for an ionic compound
We know that 2 hydrogens so the charge is +2 (normal) or -2 (metal hydride)
So we can assume that it is gonna be the group 2 metal since it readily forms +2 metal ions
so it must be D as that will be group 2

Hope that helps Itsnotaphasemom
Last edited by Boss_Rhythm; 1 year ago
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