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as level physics help😮😮

A trolley of mass 850 g is held between two fixed points by means of identical springs
When the trolley is in equilibrium, the springs are each extended by 4.5 cm. Each spring has a
spring constant of 16 N m-1.
The trolley is moved a distance of 1.5 cm along the direction of the springs. This causes the
extension of one spring to be increased and the extension of the other spring to be decreased. The
trolley is then released. The trolley accelerates and reaches its maximum speed at the equilibrium
position. Calculate:
he maximum speed of the trolley
So you need to calculate the energy stored in each of the springs when the trolley is displaced.
This energy is transferred to the cart as kinetic energy and the kinetic energy gained will be equal to elastic potential energy in the springs
finally using (mv^2)/2 you can work out the speed achieved by the trolley
Original post by shah kaivan
A trolley of mass 850 g is held between two fixed points by means of identical springs
When the trolley is in equilibrium, the springs are each extended by 4.5 cm. Each spring has a
spring constant of 16 N m-1.

If you want help with a problem like this at least show willing to engage with it. What have you tried and how far did you get ? When faced with a physics problem you dont know how to attack a good approach is to (1) work out what the information you are given tells you and (2) which underlying principle(s) are key to solving the problem.

Try throwing conservation of energy at it and see if it sticks.
i have used the formula 1/2kx^2
but was not able to get answer
so what to do
Original post by shah kaivan
so what to do

Spring extension 0.5k x^2 gives you an energy, put in numbers from the question and see what you get. Does the answer look "sensible", e.g. a reasonable size and correct units ?

Then think about how to equate this energy to something else, e.g. kinetic energy of a moving object, and try to set up a calculation arround that which produces a velocity.
i am not getting ans with this, i said
Original post by shah kaivan
i am not getting ans with this, i said


The question gives you a distance change and a spring constant ..... what did you do with those ?
Original post by shah kaivan
but was not able to get answer

have you made sure you are working out the energy stored in both of the springs.
Use the equation given in part b to calculate work. Work = KE = 1/2 mv2 then calculate v

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