FP1 First order Differentials Watch
dy/dx = y^2 . ln x
so heres wut i do:
y^-2 dy = lnx dx
-y^-1 = lnx dx...
cept i dont know how to integrate lnx
Integration by parts = u.v - (integration sign) u. v' ... yeh?
lol i wish, i had it on fri, and it feels like i haven't touched fp1 since easter, which i umm, haven't lol!
i thought i was the only one in this state of destruction lol..
so i suppose ur doing hard core revision right now eh?
e^-x^2 dy/dx = y.x
but i think im on the right track now..
You should be looking at
Then you need to divide both sides by a half to get the desired answer to your integral.