# FP1 First order DifferentialsWatch

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#1
Hi

dy/dx = y^2 . ln x

so heres wut i do:

y^-2 dy = lnx dx
-y^-1 = lnx dx...
cept i dont know how to integrate lnx
any tips??
0
11 years ago
#2
See that and use IBP.
0
11 years ago
#3
by parts, integrate 1.lnx
0
#4
ah thnx dudes...i mean dude and dudette......havent touched C4 for 4 months :P
0
11 years ago
#5
lol i wish, i had it on fri, and it feels like i haven't touched fp1 since easter, which i umm, haven't lol!
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#6
oh and heey,
Integration by parts = u.v - (integration sign) u. v' ... yeh?
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#7
(Original post by kamie)
lol i wish, i had it on fri, and it feels like i haven't touched fp1 since easter, which i umm, haven't lol!
u got FP1 too this monday??
0
11 years ago
#8
you'll be integrating x.1/x, i can't figure it out from u's and v's, i learnt words! and yes i have got fp1 on monday, and i can't do first order, second order or polar
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#9
u know how good i feel hearing that ?
i thought i was the only one in this state of destruction lol..
so i suppose ur doing hard core revision right now eh?

another Qu:
e^-x^2 dy/dx = y.x
0
11 years ago
#10

Then note that

if

then

so

So what does equal?
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#11
i think ive lost u already...cant take in the ^ and the x's lol
but i think im on the right track now..
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11 years ago
#12
its

p.s. i hate all FPs =[
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11 years ago
#13
I've latexed it, but basically im integrating the differentiated function.

You should be looking at

If

Then you need to divide both sides by a half to get the desired answer to your integral.
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