Moonfield7
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#1
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#1
With the exam just two days away on Monday...im not feeling as confident as i would like. It seems to be the most difficult exam out of all my AS levels and I was just wondering what other people think of M2?...Hard/Easy/Impossible etc.....

P.s. Feel free to post any past questions on this thread too
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Mr M
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M2 is an A2 unit so that probably explains why it seems more difficult than your other AS modules.
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mlbbrown
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It's not too bad, seem to be doing alright.

I surmise you're doing it as part of Further Maths like me.
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Alfchick60
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I should be doing some revision now...
It's not too bad, because i'm doing f.maths and have already done M3, M2 hopefully won't seem as bad.
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Blackwater
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I find it pretty easy, but then I had M3 two weeks ago so it should be. I can't really bring myself to do any more past papers/Delphis papers though since most of my energy is going into not ****ing up chemistry on thursday.
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*~#lightning*~#
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For those people who find it okay/fairly easy, what would you say are the key most important things to learn? and/or any useful tips or advice that you may have...

Are there any set things which are particularly good to learn prior to the exam?
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mlbbrown
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Learning not to mess up on an early part of a question.

Centres of masses of objects.
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mumakil142
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(Original post by *~#lightning*~#)
For those people who find it okay/fairly easy, what would you say are the key most important things to learn? and/or any useful tips or advice that you may have...

Are there any set things which are particularly good to learn prior to the exam?
Conservation of mechanical energy is (i think) the most important aspect of M2, as it underpins several of the other topics.

If you get stuck on a question, C of ME might be the way around it.

Also, make sure you can derive the equation of trajectory.

Oh, and practice LOTS of past papers.
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rackerz
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Can someone help me with a question, it is the january 2007 m2 paper question 4 part (i) and the answer is supposed to be 9290J, I was looking at the mark scheme and they had not included the gain in potential energy so I find my answer to be 9302J, can someone explain why I am wrong. My workings are work = gain in ke(0.5*80*(5^2 - 2^2)) + gain in PE(25sin20) + work out(25(70+80gsin20)) = 9302J ??
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Moonfield7
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(Original post by rackerz)
Can someone help me with a question, it is the january 2007 m2 paper question 4 part (i) and the answer is supposed to be 9290J, I was looking at the mark scheme and they had not included the gain in potential energy so I find my answer to be 9302J, can someone explain why I am wrong. My workings are work = gain in ke(0.5*80*(5^2 - 2^2)) + gain in PE(25sin20) + work out(25(70+80gsin20)) = 9302J ??
Answer should be;

Work Done = (gain in KE) + (gain in G.P.E) + (W.D. against friction)

Work Done = [(0.5 x 80 x 5^2) - (0.5 x 80 x 2^2)] + (80g x 25sin20) + (70 x 25)

Work Done = 9294J
Work Done = 9290J (3.s.f)

I think you missed the "mg" part in the gain in PE and the work out bit is an incorrect mixture of the two.
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*~#lightning*~#
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Sorry..., C of ME ? Centre of mass or something? Cheers.
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Mr M
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Having been asked twice by private message, yes, I will post answers to M2 tomorrow night. It may be a little later than usual as I have an after-school meeting.
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Moonfield7
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(Original post by *~#lightning*~#)
Sorry..., C of ME ? Centre of mass or something? Cheers.
C of ME : Conservation of Mechanical Energy is what I think he meant...i.e. when stuck you often find that you can do questions by using energy instead of what seems the instinctive method in the particular question...
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rackerz
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(Original post by Moonfield7)
Answer should be;

Work Done = (gain in KE) + (gain in G.P.E) + (W.D. against friction)

Work Done = [(0.5 x 80 x 5^2) - (0.5 x 80 x 2^2)] + (80g x 25sin20) + (70 x 25)

Work Done = 9294J
Work Done = 9290J (3.s.f)

I think you missed the "mg" part in the gain in PE and the work out bit is an incorrect mixture of the two.
thanks ive been practising questions recently, getting back into the grove of m2, since i took it in january before, ive realised what ive done wrong with those type of questions, ive been including the force of the weight of the object into work done in/out depending whether its uphill or downhill by accident or something like that, thanks tho.
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menagerie
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Answer should be;

Work Done = (gain in KE) + (gain in G.P.E) + (W.D. against friction)

Work Done = [(0.5 x 80 x 5^2) - (0.5 x 80 x 2^2)] + (80g x 25sin20) + (70 x 25)

Work Done = 9294J
Work Done = 9290J (3.s.f)
Ah I'm so thick, I kept thinking where I got the extra four joules from, completely forgetting about 3sf.
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Moonfield7
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Anyone have ideas about what might come up this year?
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Blackwater
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(Original post by Moonfield7)
Anyone have ideas about what might come up this year?
I would guess that there will be some questions on Mechanics.
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