i cant solve this

At t=0 a particle is projected vertically upwards with the speed of u m/s from point A. The particle moves freely under gravity. At time T the particle is at maximum height H above A.
H=u^2/2g.
T=u/g
The point A is 3H above the ground.
Find in terms of T the total time from the instant of projection to the instant when the particle hits the ground.
* I cant solve it help please*

Reply 1

MediocreSince01

18

Post your working, or what you’ve tried so far.

Reply 2

Nadzu

OP

12

Original post by MediocreSince01

Post your working, or what you’ve tried so far.

i erased it all.

Reply 3

mqb2766

21

Original post by Nadzu

At t=0 a particle is projected vertically upwards with the speed of u m/s from point A. The particle moves freely under gravity. At time T the particle is at maximum height H above A.
H=u^2/2g.
T=u/g
The point A is 3H above the ground.
Find in terms of T the total time from the instant of projection to the instant when the particle hits the ground.
* I cant solve it help please

You're given the time/distance to max height. If you understand how you use suvat to get these, it will help with the question.

Reply 4

nmkat

9

doing the same question currently and am stuck. did you manage to solve it?

Reply 5

mqb2766

21

Original post by nmkat

doing the same question currently and am stuck. did you manage to solve it?

Which suvat equation should you use?

Reply 6

nmkat

9

Original post by mqb2766

Which suvat equation should you use?

not entirely sure. was thinking s=ut+1/2at^2

Reply 7

mqb2766

21

Original post by nmkat

not entirely sure. was thinking s=ut+1/2at^2

Ok, so what is the problem?
Have you sketched the problem? Its probably worth splitting the trajectory into two phases, the time to maximum height then the time to hit the ground.

i cant solve this

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