eipi
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#1
Report Thread starter 11 years ago
#1
How do i differentiate sec^2(x+\frac{\pi}{4})
What am i missing?
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forgottenromeo
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#2
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you look sec^2 up in the formula book (it should be there) then you need to do the product rule. and that should give you an answer -i hope-
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Arsenal4life
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or possibly the chain rule thing I think it is
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eipi
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#4
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No sec^2 isn't in the formula book, only the integral of it - tanx
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qgujxj39
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#5
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If you have any function, then adding a constant within that function (if you know what I mean) doesn't make any difference. For example: (c is a constant)
\frac{d}{dx} \sin (x + c) = \cos (x + c)
\frac{d}{dx} (x + c)^3 = 3(x + c)^2
In general, if \frac{d}{dx} f(x) = f'(x), then \frac{d}{dx} f(x + c) = f'(x + c). You can apply this logic to the differentiation you're trying to do.
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eipi
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Yes i know, i can't integrate
sec^2(x) either
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qgujxj39
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#7
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If you're stuck on differentiating sec^2 x, then use chain rule, the derivative of sec x is in the formula book.
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Pixie-Goblin
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#8
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EDIT: above post nulls suggestion
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Daniel Freedman
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#9
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(Original post by eipi)
Yes i know, i can't integrate
sec^2(x) either
Have you managed to differentiate?

 \sec^2{x} = (\sec{x}})^2

The derivative of secx is secx tanx. Use the chain rule.

To integrate,  \sec^2{x} is the derivative of tanx... (it's in the formula book)
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forgottenromeo
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#10
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yup remember sec^2 = (cos x)^-2
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