Oh how I loathe geometry...
(axb).(cxd) = (b.d)(a.c) - (b.c)(a.d)
any help would be great.
[EDIT] Oh wait, I just found it in a book. Hooray! That was a bit of a waste of your time reading this, so here's a bit of for your troubles.
[EDIT AGAIN] hmm, where does (axb)x(cxd) lie in relation to the planes through O spanned by a&b, and c&d??
Turn on thread page Beta
Vector Quadruple Products anyone? watch
- Thread Starter
- 11-11-2004 15:48
- 11-11-2004 18:13
axb is perpendicular to the plane spanned by a and b, and similarly for cxd, so (axb)x(cxd) is perpendicular to each of these and is therefore the direction of the line of the intersection of the two planes. Because the lines go through the origin, then it is infact the line of intersection, not just the direction.