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A level chemistry help - rates

Why does doubling temperature have a greater effect on the rate of reaction than doubling concentration? The rate equation given is:
Rate=k[E]
Is it because there is only one reactant, so it will be bond breaking to form the products, so doubling the temp helps to break bonds faster than doubling the conc which would just mean more molecules would have to break bonds?

Reply 1

lollypenguin

doubling the concentration just doubles the number of particles there - which does make it more likely for a collision to occur (so a greater rate of reaction) but doubling the temperature means more molecules will have the activation energy (key point!!!) which is required for particles to react therefore increasing the rate of reaction more