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    Please help
    Why can salbutamol be used as a pharmaceutical as a single optical isomer?
    Also, what organic product will be formed when it's reacted with K2CrO7/H2SO4 under reflux? :confused:
    Thanku x
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    I can answer the first question for you, but not the second without knowing salbutamol's chemical structure.

    Pharmaceutical compounds with two optical isomeric forms can cause harmful side-effects if the wrong isomer is mixed in. The correct isomer would bind with the right receptors/enzymes due to its specific shape, but the other isomer would bind to receptors/enzymes that you don't want it to because its shape is not the same. This could mean that the medicine has a reduced effect or increased side-effects.

    Regarding the second question, refluxing with acidified potassium dichromate will cause it to be oxidised, but there's several different products depending on the reactant, hence I need to know its chemical structure.
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    (Original post by madmazda86)
    I can answer the first question for you, but not the second without knowing salbutamol's chemical structure.

    Pharmaceutical compounds with two optical isomeric forms can cause harmful side-effects if the wrong isomer is mixed in. The correct isomer would bind with the right receptors/enzymes due to its specific shape, but the other isomer would bind to receptors/enzymes that you don't want it to because its shape is not the same. This could mean that the medicine has a reduced effect or increased side-effects.

    Regarding the second question, refluxing with acidified potassium dichromate will cause it to be oxidised, but there's several different products depending on the reactant, hence I need to know its chemical structure.

    Thankyou once again umm it's hard to show the chemical structure on here. On the left it has one carbon attached to 3 CH3 groups and a nitrogen. The nitrogen is attached to a hydrogen and a carbon. From this carbon is 2 Hs and a carbon. From this carbon is an H, an OH group and a benzene ring,and from the ring is an OH group and a carbon. From this last carbon is an OH group and two H groups. Sorry this explanation is so crappy...
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    (Original post by lil_crazyflakes)
    Thankyou once again umm it's hard to show the chemical structure on here. On the left it has one carbon attached to 3 CH3 groups and a nitrogen. The nitrogen is attached to a hydrogen and a carbon. From this carbon is 2 Hs and a carbon. From this carbon is an H, an OH group and a benzene ring,and from the ring is an OH group and a carbon. From this last carbon is an OH group and two H groups. Sorry this explanation is so crappy...
    Okay, I think I have it... sadly I'm not totally sure of the answer I can see a two secondary alcohol groupings and one primary... in which case it might oxidise to either an aldehyde/carboxylic acid or a ketone. I did the standard OCR rather than Salters so I dunno if this is of much use.
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    (Original post by madmazda86)
    Okay, I think I have it... sadly I'm not totally sure of the answer I can see a two secondary alcohol groupings and one primary... in which case it might oxidise to either an aldehyde/carboxylic acid or a ketone. I did the standard OCR rather than Salters so I dunno if this is of much use.
    Iam doing OCR too, thanku for trying to help, i think i'm making it sound more complicated than it is...
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    This is salbutamol, in case someone else wants to have a go at it.



    I think I have heard something about an intermediate permanganate diester, which would serve as an example of chemiluminescence. Don't really know if that's the same with perchromate, though.
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    (Original post by Jinsho)
    This is salbutamol, in case someone else wants to have a go at it.



    I think I have heard something about an intermediate permanganate diester, which would serve as an example of chemiluminescence. Don't really know if that's the same with perchromate, though.
    Sorry ... I search the image for salbutamol on Google but ... I don't have the same image like urs
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    Salbutamol is 4-(2-(tert-butylamino)-1-hydroxyethyl)-2-(hydroxymethyl)phenol, if I am not mistaken. This is exactly the picture I showed.

    Here are some other pictures of salbutamol (albuterol).





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    In that case I'd guess carboxylic acid will be produced. (The C-OH will be replaced by C=O(OH) )
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    Thanks for all your help everyone x
 
 
 

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