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As level / a level chemistry concentration help!!

The table shows the student’s results.
Titration 1 Titration 2 Titration 3 Titration 4 Titration 5
Volume of 13.50 12.10 11.10 12.15 12.15
citric acid
in Cm3


The equation for the reaction is:
C6H8O7 + 3 NaOH C6H5O7Na3 + 3 H2O

The concentration of the sodium hydroxide was 0.102 mol / dm3
Concordant results are those within 0.10 cm3 of each other.

Calculate the concentration of the citric acid in mol / dm3
Use only the concordant results from the table in your calculation.
You must show your working. (5)
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Do you know the volume of NaOH? (I can't seem to work out moles otherwise?)
(edited 4 years ago)
Reply 2
Original post by AliceV_647
Do you know the volume of NaOH? (I can't seem to work out moles otherwise?)

Nope it is not given, I know we we can work out the volume of the citric acid by dividing by 1000 for each titration
Reply 3
Original post by kdb171997
Nope it is not given, I know we we can work out the volume of the citric acid by dividing by 1000 for each titration

Original post by AliceV_647
Do you know the volume of NaOH? (I can't seem to work out moles otherwise?)

Part a states this

A student titrated citric acid with sodium hydroxide solution.
This is the method used.
1. Pipette 25.0 cm3 of sodium hydroxide solution into a conical flask.
2. Add a few drops of thymol blue indicator to the sodium hydroxide solution.
Thymol blue is blue in alkali and yellow in acid.
3. Add citric acid solution from a burette until the end-point was reached.



(Would the volume be 25cm3???? for naoh)
Original post by kdb171997
Nope it is not given, I know we we can work out the volume of the citric acid by dividing by 1000 for each titration

Hmm... I've got the mean titre for the citric acid (0.01213 dm3 if I'm right?)

Original post by kdb171997
Part a states this

A student titrated citric acid with sodium hydroxide solution.
This is the method used.
1. Pipette 25.0 cm3 of sodium hydroxide solution into a conical flask.
2. Add a few drops of thymol blue indicator to the sodium hydroxide solution.
Thymol blue is blue in alkali and yellow in acid.
3. Add citric acid solution from a burette until the end-point was reached.



(Would the volume be 25cm3???? for naoh)

Yep, that's the volume! Give me a sec and I'll see if I can work the rest out :smile:
Have you got a mark scheme/answer for the question? I've got an answer of 0.070mol.dm3 but obviously I can't be sure that it's right (it's been a few months since I've done any A level chem!)

I'll just type out my workings now :smile:
Reply 6
Original post by AliceV_647
Have you got a mark scheme/answer for the question? I've got an answer of 0.070mol.dm3 but obviously I can't be sure that it's right (it's been a few months since I've done any A level chem!)

I'll just type out my workings now :smile:

Thanks for your quick replies.. I'm honestly not too sure myself hence I asked on Student room :smile:
There is a link which contains the answer (the last question)
but I can't open the link as it is a DOC file and not a PDF
Could you try to check if the link opens for you
titration_markscheme.doc - singhscience
Okay, so my workings (again, can't promise this is right!):

25cm3 = 0.025dm3

mol of NaOH = concentration X volume = 0.102 x 0.025 = 2.55x10-3 (0.00255)

therefore mol of citric acid = 2.55x10-3 divided by 3 (as the ratio of NaOH to citric acid is 3:1) = 8.5x10-4

mean titre of citric acid = (12.10 + 12.15 + 12.15) / 3 = 12.13cm3

12.13/1000 = 0.01213 dm3 of citric acid

concentration = mol/vol, therefore conc of citric acid = 8.5x10-4 / 0.01213 = 0.070mol.dm3


No clue if that's the right answer, but that's what I got!
Original post by kdb171997
Thanks for your quick replies.. I'm honestly not too sure myself hence I asked on Student room :smile:
There is a link which contains the answer (the last question)
but I can't open the link as it is a DOC file and not a PDF
Could you try to check if the link opens for you
titration_markscheme.doc - singhscience

No problem - I've been going a bit crazy with no work to do since A levels so it's nice to get to use my brain haha!
I'll try to open it now :smile:
Reply 9
Original post by AliceV_647
Okay, so my workings (again, can't promise this is right!):

25cm3 = 0.025dm3

mol of NaOH = concentration X volume = 0.102 x 0.025 = 2.55x10-3 (0.00255)

therefore mol of citric acid = 2.55x10-3 divided by 3 (as the ratio of NaOH to citric acid is 3:1) = 8.5x10-4

mean titre of citric acid = (12.10 + 12.15 + 12.15) / 3 = 12.13cm3

12.13/1000 = 0.01213 dm3 of citric acid

concentration = mol/vol, therefore conc of citric acid = 8.5x10-4 / 0.01213 = 0.070mol.dm3


No clue if that's the right answer, but that's what I got!

Seems like a nice and clear response Alice :smile:

Would you explain why you did this step [mean] and why you added these three and not all the volumes please
Hmm, I can't seem to find it - is it a part of a question (e.g. a), b), c) etc)?
Reply 11
Original post by kdb171997
Seems like a nice and clear response Alice :smile:

Would you explain why you did this step [mean] and why you added these three and not all the volumes please

You only add concordant titres, defined as titres within 0.1cm^3 of each other.
Reply 12
Original post by AliceV_647
Hmm, I can't seem to find it - is it a part of a question (e.g. a), b), c) etc)?

Here are the questions
http://www.singhscience.co.uk/uploads/2/4/1/3/24135648/titration_questions.pdf

I think it's 1d
Ah brilliant thank you! I found it - I was right! (Just didn't give enough decimal places... whoops!) Hopefully my screenshot of the mark scheme will show up...


Screenshot 2019-09-14 at 22.03.58.png
Reply 14
Original post by Deggs_14
You only add concordant titres, defined as titres within 0.1cm^3 of each other.

Ahh makes sense! Ty
Original post by kdb171997
Seems like a nice and clear response Alice :smile:

Would you explain why you did this step [mean] and why you added these three and not all the volumes please

When you're finding the mean titre, you only use concordant titres - these are titres that are within 0.1cm3 of each other. You then find the mean from these and discard all other titres - that way your results are more accurate!

And yay - I'm glad my explanation wasn't completely garbage haha!
Reply 16
Original post by AliceV_647
When you're finding the mean titre, you only use concordant titres - these are titres that are within 0.1cm3 of each other. You then find the mean from these and discard all other titres - that way your results are more accurate!

And yay - I'm glad my explanation wasn't completely garbage haha!

It seems you could easily be a chem teacher haha! :smile:
Original post by kdb171997
It seems you could easily be a chem teacher haha! :smile:

Haha, I wish! But thank you :smile:
Reply 18
Original post by AliceV_647
Ah brilliant thank you! I found it - I was right! (Just didn't give enough decimal places... whoops!) Hopefully my screenshot of the mark scheme will show up...


Screenshot 2019-09-14 at 22.03.58.png

Thats perfect! Your a star! I had doubts if I should upload to student room because I didn't expect to get any reps that quick haha, I hope you do well in your chosen career!.. BLESS U
Reply 19
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Original post by AliceV_647
When you're finding the mean titre, you only use concordant titres - these are titres that are within 0.1cm3 of each other. You then find the mean from these and discard all other titres - that way your results are more accurate!

And yay - I'm glad my explanation wasn't completely garbage haha!

You explained your process to answer this question wonderfully and very clearly. Praises to you.

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